Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
277 comments Page 23 of 28.
Pria said:
8 years ago
What is reference point?
Bikash said:
8 years ago
If the man stand at the head side then the length of train is 300m as well as the length of the platform is 240 m and if the man stand at any point of the platform then the length of the platform is 540.
Gaurav said:
8 years ago
A simple one trick:
Here train crosses a platform and a man standing on a platform in the same direction i.e. 36 - 20 = 16 sec is relative timing.
And speed of the train is 54 km/hr i.e. 15 m/sec
Now we have speed and time then apply formula;
The solution is length= 15 x 16 = 240 m.
That's all.
Thank you.
Here train crosses a platform and a man standing on a platform in the same direction i.e. 36 - 20 = 16 sec is relative timing.
And speed of the train is 54 km/hr i.e. 15 m/sec
Now we have speed and time then apply formula;
The solution is length= 15 x 16 = 240 m.
That's all.
Thank you.
Irfan Zahir said:
7 years ago
Speed conversion, 54*(5/18)= 15 m/s.
Length of both Train and Platform is;
D=S*T,
= 15*36,
= 540 (It includes the length of both train and platform).
Again,
D=S*T
=15*20,
= 300 (It is the length of only train),
Now the length of the platform = 540-300= 240 meter.
Length of both Train and Platform is;
D=S*T,
= 15*36,
= 540 (It includes the length of both train and platform).
Again,
D=S*T
=15*20,
= 300 (It is the length of only train),
Now the length of the platform = 540-300= 240 meter.
Prajeesh said:
7 years ago
Speed conversion, 54*(5/18)= 15 m/s.
Length of train =15*20= 300m.
Formula:
The length of train= [length of platform/diffrence in time ]*time taken to cross stationary pole or man.
300=[x/36-20]20,
x=1200/5,
x =240m.
Length of train =15*20= 300m.
Formula:
The length of train= [length of platform/diffrence in time ]*time taken to cross stationary pole or man.
300=[x/36-20]20,
x=1200/5,
x =240m.
Rakshith said:
7 years ago
Can anybody explain me why are we taking 36-20, and Why 540-300?
Please explain this step.
Please explain this step.
Mounika said:
7 years ago
36 sec is the length of the train and platform. 20 seconds is the length of the train.
So, the length of the platform is 36-20=16 sec.
54*5/18 = 15m/sec is the speed of the train.
The length of the platform = 15*16 = 240.
So, the length of the platform is 36-20=16 sec.
54*5/18 = 15m/sec is the speed of the train.
The length of the platform = 15*16 = 240.
Ani said:
7 years ago
Net time = 36-20 = 16,
So length of platform is =time * speed,
That is=16x15=240 MTR.
So length of platform is =time * speed,
That is=16x15=240 MTR.
Bhuwan Ranjan said:
7 years ago
Answer will be 240mt but the length of the train is more than the platform.
Rajesh said:
7 years ago
54 * (5/18) * (36-20)=240 is the correct method I think.
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