Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 21 of 28.
Er.Shubham said:
7 years ago
@Krishna,
Don't compare the Length of both.
Take only the starting and ending point.
Don't compare the Length of both.
Take only the starting and ending point.
Nisha said:
7 years ago
Thanks, @Vetri.
Kavya said:
7 years ago
Very good answer @Vetri.
Shivam singh said:
7 years ago
Km/h to m/s.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
Manisha dambe said:
7 years ago
Time to pass platform = 16s,
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.
Harsh said:
7 years ago
I think the answer should be 540.
Because, how can the length of the platform be less than the length of the trian?
Because, how can the length of the platform be less than the length of the trian?
Somnath sen said:
7 years ago
Anyone Please explain it for me.
Sagar Dombale said:
7 years ago
What is 5/18? Please explain me.
Jesudas said:
7 years ago
@Sagar Dombale.
It's the conversion of km/h to m/s.
It's the conversion of km/h to m/s.
Remee Rahul said:
6 years ago
Does the man standing on the starting/intial point of the platform?
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