Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
120 m
240 m
300 m
None of these
Answer: Option
Explanation:

Speed = 54 x 5 m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

x + 300 = 540

x = 240 m.

Discussion:
276 comments Page 21 of 28.

Guru said:   1 decade ago
The time taken by train to cross platform is=36-20=16sec.

Speed of train=54*(5/18)m/s.

Distance(length)=speed*time.

=54*(5/18)*16.

=240m.

Priyanka said:   1 decade ago
Train passes in 36 secs, man standing in 20 secs.
therefor, 36-20= 16 secs.
now, speed = 54 km/hr.
= {54 X 5/18} = 15 m/sec.
here, length = speed X time
= 15 X 16
= 240 m. ans

Surender Kashyap said:   1 decade ago
L/20 = (L+P)/36 = 54*5/18
using compenondo and dividendo means (L+P)-L/36-20
P/16 = 15
SO, P = 15*16
P = 240

Shiji said:   1 decade ago
Why don`t we take the length of the train=15*36.

Gopu said:   1 decade ago
Simple method;.
Convert train speed into m/sec=54*5/18.
=15m/s.
Subtract train time which it had taken to cross a man from the time taken by train to cross the platform i.e,
= (36-20).
=16.
Now apply formula of distance i.e. speed*time.
=15*16.
=240. ) ).

Ravinder Kumar said:   1 decade ago
The simple method is
Train speed is 54km/h*5/18=15m/second
Time taken between man standing on platform and station platform ( 36-20) = 16 sec.
Distance= 15*16 = 240m

Prakash ranjan naik said:   1 decade ago
Train speed=15m/s
Time=20s
If train pass man means,that is the tme of train
That's why
Length of train=15x20

Praveen prabhakar said:   1 decade ago
Distance=speed*time
Distance=(54*5/18)*(36-20)=240m

Sudhapriya said:   1 decade ago
Thank you vetri. I gained answer from you.

Veeresh said:   1 decade ago
xkmph means train goes x meters in 3.6 seconds. here 36-20secs required to travel for the train to pass platform.
3.6 sec---->54 meters
16 secs---->?
16/3.6x54=240 meters


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