Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
Speed = | ![]() |
54 x | 5 | ![]() |
18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, | x + 300 | = 15 |
36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 18 of 28.
Gaurav pandey said:
1 decade ago
Yeah I have same question that why are we taking 15*20?
Sibu said:
1 decade ago
If the man is at starting point of platform then answer is 240.
If the man is at any where of the platform then answer is 540.
If the man is at any where of the platform then answer is 540.
Veera said:
1 decade ago
They have asked for total length of the platform and answer must be 300+240 = 540 mt. Am I right ? can anyone help me clear my doubt.
Najma said:
1 decade ago
I think it should be the logic, initially total length of the train couldn't on platform. It takes 20 sec (reference point where the man stand) to be on platform completely. From that reference point only the train completely travels on platform. That why we are subtracting the time 36-20=16sec it is the time train completely on platform.
Now calculate length = (54*5/18) *16 sec = 240 sec.
Friends. Am I correct?
Now calculate length = (54*5/18) *16 sec = 240 sec.
Friends. Am I correct?
Savitha said:
1 decade ago
@Vinod you have done a mistake 36-20 k be careful while doing.
Vinod Anand said:
1 decade ago
When Speed is =54km/h than 54*5/18.
Speed = 15 m/sec.
Now time are = 30-26 = 16 sec.
The length of the Platform is = 15*16.
= 240 m. (B).
Speed = 15 m/sec.
Now time are = 30-26 = 16 sec.
The length of the Platform is = 15*16.
= 240 m. (B).
Ramkumar said:
1 decade ago
Speed = 54*(5/18) = 15m/s.
Now time = 36-20 = 16.
Now distance(i.e length) = speed*time.
= 15*16.
= 240m/s.
This is way of correct. Please explain.
Now time = 36-20 = 16.
Now distance(i.e length) = speed*time.
= 15*16.
= 240m/s.
This is way of correct. Please explain.
Rahul said:
1 decade ago
We can do it like this.
Train run in 36sec, so 36 * 15 = 540. Train run in 20 sec, so 20 * 15 = 300.
Ans: 540 - 300 = 240.
Train run in 36sec, so 36 * 15 = 540. Train run in 20 sec, so 20 * 15 = 300.
Ans: 540 - 300 = 240.
Gaurav said:
1 decade ago
Can we do it on this way.
In 36 second train run 36 x 15 = 540 m.
In 20 second train run 20 x 15 = 300 m.
And the length of platform is 540 - 300 = 240 mtr.
In 36 second train run 36 x 15 = 540 m.
In 20 second train run 20 x 15 = 300 m.
And the length of platform is 540 - 300 = 240 mtr.
Dinesh said:
1 decade ago
Man is standing on the platform how can you subtract?
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