Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = | ![]() |
54 x | 5 | m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
282 comments Page 13 of 29.
Umair Kabeer said:
9 years ago
According to my understanding,
1- In 36s train passes the total length which is unknown.
2- In 20s train passes the man which will be our reference point to calculate the speed.
So, from formula: Length or Distance = Time * Speed.
Length of train = 20s * 54(1000/60 * 60).
Length of train = 300 m.
Total length (Platform & train) = 36s * 54(1000/60 * 60).
Total length (Platform & train) = 540m.
Platform length = Total length = Train length = 540 -300 = 240m.
1- In 36s train passes the total length which is unknown.
2- In 20s train passes the man which will be our reference point to calculate the speed.
So, from formula: Length or Distance = Time * Speed.
Length of train = 20s * 54(1000/60 * 60).
Length of train = 300 m.
Total length (Platform & train) = 36s * 54(1000/60 * 60).
Total length (Platform & train) = 540m.
Platform length = Total length = Train length = 540 -300 = 240m.
Rahul Baranwal said:
9 years ago
I think there should be clarified in the question. That the man is exactly standing the place as the train is long.
Then only we can take the train length according to given solution.
Otherwise, the solution is wrong.
Then only we can take the train length according to given solution.
Otherwise, the solution is wrong.
Santanu Pratihar said:
9 years ago
I am unable to understand it. Someone help me.
Thiyagu said:
9 years ago
54 * (5/18) = 15m.
x = 36s y = 20s.
x - y = 16s (dist b/w train reach the station - train reach the man).
Now,
15 * 16 = 240m (speed * dist).
Answer = 240m.
x = 36s y = 20s.
x - y = 16s (dist b/w train reach the station - train reach the man).
Now,
15 * 16 = 240m (speed * dist).
Answer = 240m.
Raj said:
9 years ago
Distance = time * speed.
Sspeed of train = 54 * 5/18 = 15 m/s.
Time taken by train to cross man= 20s,
Therefore distance/length of train = 20 * 15 = 300m,
Time taken to cross platform= 36s.
Length of train + length of platform = time * speed.
Which implies,
Length of platform = (36 * 15) - length of train.
Length of platform = 540 - 300,
Length of platform = 240m.
Sspeed of train = 54 * 5/18 = 15 m/s.
Time taken by train to cross man= 20s,
Therefore distance/length of train = 20 * 15 = 300m,
Time taken to cross platform= 36s.
Length of train + length of platform = time * speed.
Which implies,
Length of platform = (36 * 15) - length of train.
Length of platform = 540 - 300,
Length of platform = 240m.
Nandhu said:
10 years ago
Speed of the train = 54km/hr,
= 54 * 5/18 m/s,
= 15 m/s.
Time = train reach time - man standing time.
= 36 - 20,
= 16s.
Length = Speed * time.
= 15 * 16.
= 240m.
= 54 * 5/18 m/s,
= 15 m/s.
Time = train reach time - man standing time.
= 36 - 20,
= 16s.
Length = Speed * time.
= 15 * 16.
= 240m.
Harry said:
10 years ago
SIMPLE WAY.
Speed = 54km/hr,
54/3600 * 1000,
=15m/s.
36 sec to pass the platform
15 * 36 = 540.
20 sec to pass the man,
15 * 20 = 300.
i.e distance is 540 - 300 = 240.
Speed = 54km/hr,
54/3600 * 1000,
=15m/s.
36 sec to pass the platform
15 * 36 = 540.
20 sec to pass the man,
15 * 20 = 300.
i.e distance is 540 - 300 = 240.
Rjay said:
10 years ago
There are a platform and train is passing through that platform in 36 seconds and there is a man ON THE PLATFORM, the train passes it in 20 sec. You cannot add both the times because man is standing on the platform. If he were standing outside the platform timings could have been added.
So, Trains speed is 15 m/s and it is a crossing platform in 36 seconds and men is included in it coz he is standing on the platform.
So length of train + length of platform will be = 15 multiply 36 = 540.
Now the length of the platform (you have to subtract the length of the train from total length) = 15 multiply 20 = 300.
So, 540 - 300 = 240.
So, Trains speed is 15 m/s and it is a crossing platform in 36 seconds and men is included in it coz he is standing on the platform.
So length of train + length of platform will be = 15 multiply 36 = 540.
Now the length of the platform (you have to subtract the length of the train from total length) = 15 multiply 20 = 300.
So, 540 - 300 = 240.
Sai said:
10 years ago
Length = Speed * Time.
Speed = 54 * 5/18 = 15 m/sec.
Time = 36 - 20 = 16.
Length = 15 * 16.
= 240m.
Speed = 54 * 5/18 = 15 m/sec.
Time = 36 - 20 = 16.
Length = 15 * 16.
= 240m.
Peter said:
10 years ago
Easily way.
Train speed is 54 in KM/HR so KM/HR = 1000 M /3600 S = 10/36 = 5/18 * 54 train speed = 15 M/S.
Train crossed in 36 man in 20 so we can minus both so 36 - 20 = 16.
16 * 15 = 240.
Train speed is 54 in KM/HR so KM/HR = 1000 M /3600 S = 10/36 = 5/18 * 54 train speed = 15 M/S.
Train crossed in 36 man in 20 so we can minus both so 36 - 20 = 16.
16 * 15 = 240.
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m/sec = 15 m/sec.