Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 12)
12.
A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
Answer: Option
Explanation:
| Speed = |  |
72 x | 5 |  m/sec |
= 20 m/sec. |
| 18 |
Time = 26 sec.
Let the length of the train be x metres.
| Then, | x + 250 | = 20 |
| 26 |
x + 250 = 520
x = 270.
Discussion:
39 comments Page 3 of 4.
Sandip said:
1 decade ago
At 72 km/hr train goes 520 mt.
Length of the plat form = 250.
So length of the train = 520-250 = 270.
Length of the plat form = 250.
So length of the train = 520-250 = 270.
Sarang said:
7 years ago
Distance =speed *time.
D=72km/h*26,
D=72*5/18*26,
D=4*5*26,
D=20*26,
D=520-250=270m.
D=72km/h*26,
D=72*5/18*26,
D=4*5*26,
D=20*26,
D=520-250=270m.
(4)
Jeevan said:
1 decade ago
= 72*5/18.
= 36*5/9.
= 4*5.
= 20.
d = Sp*ti.
20*26.
= 520-250.
= 270.
= 36*5/9.
= 4*5.
= 20.
d = Sp*ti.
20*26.
= 520-250.
= 270.
Sonia said:
1 decade ago
why x+250?.....for same direction we take sbtraction....then why it is added?
Madhav Kulkarni said:
5 years ago
Speed=(L1+L2)/2.
72*(5/18)=(250+L2)/26,
L2=(20*26)-250,
=520-250.
=270.
72*(5/18)=(250+L2)/26,
L2=(20*26)-250,
=520-250.
=270.
(1)
Akber said:
1 decade ago
@Sania.
Here platform is stationary that is the reason we are adding.
Here platform is stationary that is the reason we are adding.
Sujith.m said:
1 decade ago
(x+250)/26=20 Can anybody explain how to come this?
Sonam said:
1 decade ago
Ya. But why only 5/18 why not some other numbers?
Yogesh said:
1 decade ago
x + 250 = 520, how 520 has come, please explain.
Donald Pinto said:
1 decade ago
Hi Dinesh Thankyou so much for the explanation!!
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