Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
| Speed = |  |
45 x | 5 |  m/sec |
= | |
25 | m/sec. |
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
254 comments Page 20 of 26.
Sonik Salam said:
5 years ago
260+2x=750.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
(1)
Vaghela Milankumar said:
3 years ago
4.5x 5/18 = 12.5
12.5 x 30 = 375
375 - 130 = 245 ans.
12.5 x 30 = 375
375 - 130 = 245 ans.
(55)
Kiranmaye said:
3 years ago
@Rajesh.
We take 5/18 to convert from km/h into m/s.
We take 5/18 to convert from km/h into m/s.
(24)
Mubeen said:
2 decades ago
@Coolburn
Yep... Quite simple and understandable.
Yep... Quite simple and understandable.
Mayu said:
1 decade ago
Yes shahul I like your tact to solve this problem.
Radha said:
1 decade ago
Please explain method clearly how we will dot 750?
Deep said:
1 decade ago
Easy method is by using time and distance formula.
Sandhya said:
10 years ago
Can you explain me in detail? I can't understand.
Madan said:
1 decade ago
45*5/18 = 12.5.
12.5*30 = 375.
375-130 = 245.
12.5*30 = 375.
375-130 = 245.
Poonam Pipaliya said:
1 decade ago
What is role of 30 sec and from where it comes?
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