Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
| Speed = |  |
45 x | 5 |  m/sec |
= | |
25 | m/sec. |
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
252 comments Page 19 of 26.
Reethu said:
1 decade ago
Hi,
Can anyone explain what is 5/18 here? I couldn't get this.
Can anyone explain what is 5/18 here? I couldn't get this.
Anjaneyulu said:
1 decade ago
Hi,
Can anyone explain what is 5/18 here? I couldn't get this.
Can anyone explain what is 5/18 here? I couldn't get this.
Maanvi said:
10 years ago
@Naveen Kumawat.
Nice description to understand the problem.
Nice description to understand the problem.
TheInternetGuy said:
1 decade ago
Is 45 km/hr relative speed between the bridge and the train?
Arundeep said:
1 decade ago
First of all arragne them in D= ST.
S = D/T or T = D/S.
S = D/T or T = D/S.
Moin ashraf said:
9 years ago
Distance = velocity x time.
130+x = (25/2)x30,
x = 245.
130+x = (25/2)x30,
x = 245.
DURAI said:
8 years ago
@Rahul.
Your explanation is clear my doubt thank you.
Your explanation is clear my doubt thank you.
Kavya said:
6 years ago
D= S * T.
D = 45 * 5/18 * 30 = 375m,
375-130=245m.
D = 45 * 5/18 * 30 = 375m,
375-130=245m.
(2)
Sonik Salam said:
5 years ago
260+2x=750.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
(1)
Vaghela Milankumar said:
3 years ago
4.5x 5/18 = 12.5
12.5 x 30 = 375
375 - 130 = 245 ans.
12.5 x 30 = 375
375 - 130 = 245 ans.
(55)
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