Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
| Speed = |  |
45 x | 5 |  m/sec |
= | |
25 | m/sec. |
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
247 comments Page 19 of 25.
Arundeep said:
1 decade ago
First of all arragne them in D= ST.
S = D/T or T = D/S.
S = D/T or T = D/S.
Moin ashraf said:
8 years ago
Distance = velocity x time.
130+x = (25/2)x30,
x = 245.
130+x = (25/2)x30,
x = 245.
DURAI said:
8 years ago
@Rahul.
Your explanation is clear my doubt thank you.
Your explanation is clear my doubt thank you.
Kavya said:
6 years ago
D= S * T.
D = 45 * 5/18 * 30 = 375m,
375-130=245m.
D = 45 * 5/18 * 30 = 375m,
375-130=245m.
(2)
Sonik Salam said:
4 years ago
260+2x=750.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
2x=750-260,
2x=490,
And x = 490/2 = 245m.
(1)
Vaghela Milankumar said:
3 years ago
4.5x 5/18 = 12.5
12.5 x 30 = 375
375 - 130 = 245 ans.
12.5 x 30 = 375
375 - 130 = 245 ans.
(55)
Kiranmaye said:
2 years ago
@Rajesh.
We take 5/18 to convert from km/h into m/s.
We take 5/18 to convert from km/h into m/s.
(23)
Mubeen said:
1 decade ago
@Coolburn
Yep... Quite simple and understandable.
Yep... Quite simple and understandable.
Mayu said:
1 decade ago
Yes shahul I like your tact to solve this problem.
Radha said:
1 decade ago
Please explain method clearly how we will dot 750?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers