Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 8 of 59.
Bangaru said:
1 decade ago
@Divya.
Can you explain the problem which was mentioned by you ?
Can you explain the problem which was mentioned by you ?
Srikanth said:
1 decade ago
Can you explain the problem with diagrammatic representation ?
ANIL said:
1 decade ago
@Bangaru.
If the total salary is 100%, in which 15% spent on insurance policy means 100-15 =85%.
55% spent as expenditure on shopping etc means 85-55 =30%
Savings =salary -expenditure.
30% savings equals to 12,750.
Percentage can be represented as per hundred i.e., 30/100, which is equals to 12,750.
Assume that total salary be X
X *30/100 =12,750
X =12750*100/30
X= 42500.
If the total salary is 100%, in which 15% spent on insurance policy means 100-15 =85%.
55% spent as expenditure on shopping etc means 85-55 =30%
Savings =salary -expenditure.
30% savings equals to 12,750.
Percentage can be represented as per hundred i.e., 30/100, which is equals to 12,750.
Assume that total salary be X
X *30/100 =12,750
X =12750*100/30
X= 42500.
Manoranjan samal said:
1 decade ago
Let length of the train be 'x' metres...
Speed of the train = 60km/hr(given)
Time = 9seconds(given)
Refer the formulas for train problems...
As the time is given in seconds and answers are given in metre(train length) We are in need to convert from km/hr to m/s
km/hr = 1000m/(60min*60sec) = 5/18 m/s
Length of the train(distance covered a post)= speed * time
= (60*(5/18))*9
= (50/3)*9
= 150 m
For the train related formulas,check the READ MORE in Left corner(Important formulas)...
Speed of the train = 60km/hr(given)
Time = 9seconds(given)
Refer the formulas for train problems...
As the time is given in seconds and answers are given in metre(train length) We are in need to convert from km/hr to m/s
km/hr = 1000m/(60min*60sec) = 5/18 m/s
Length of the train(distance covered a post)= speed * time
= (60*(5/18))*9
= (50/3)*9
= 150 m
For the train related formulas,check the READ MORE in Left corner(Important formulas)...
Srinu said:
1 decade ago
We know that
1km=1000meters
1hr=3600seconds
1km/1hr=1000/3600=10/36=5/18m/s
1km/hr=5/18m/s
60km/hr=(60*5/18).
1km=1000meters
1hr=3600seconds
1km/1hr=1000/3600=10/36=5/18m/s
1km/hr=5/18m/s
60km/hr=(60*5/18).
Jagadeesh said:
1 decade ago
Here, give train travels at a speed of (60*5/18) m/s, that is for one second it travels a distance of 50/3 m/s. So the distance traveled for 9 seconds gives the actual length of train, that is 50/3*9=150m.
Kishan said:
1 decade ago
Similarly,
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Raj said:
1 decade ago
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
50/3*9 = 150mtrs.
Rasu said:
1 decade ago
Speed convert km/h to m/sec speed=[60*5/18]m/sec
speed=[50/3]m/sec.
Distance=[speed*time]
Length of the train=[50/3*9]
=150m.
speed=[50/3]m/sec.
Distance=[speed*time]
Length of the train=[50/3*9]
=150m.
SANTOSH, aps, goregaon said:
1 decade ago
Total exp= 15%+55%= 70%
Let salary rs.100
Save= 100-70= Rs.30%
Rs.30%= 12750.
100% = 12750/30x100=42500.
Let salary rs.100
Save= 100-70= Rs.30%
Rs.30%= 12750.
100% = 12750/30x100=42500.
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