Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
613 comments Page 8 of 62.
Saipriya said:
1 year ago
1km = 1000m,
1hr = 3600s.
1km/hr = 1000/3600.
= 5/18 m/s.
1hr = 3600s.
1km/hr = 1000/3600.
= 5/18 m/s.
(38)
Nrsp said:
1 year ago
Convert km/h to m/s.
1km = 1000m.
1hour = 3600sec.
Speed = 60km/h.
= 60 × 1000/3600,
= 60 × (5/18),
= 50/3.
1km = 1000m.
1hour = 3600sec.
Speed = 60km/h.
= 60 × 1000/3600,
= 60 × (5/18),
= 50/3.
(16)
Ivan said:
1 year ago
I still don't understand. How 5/18 came? Please explain to me.
(20)
Gowrishankar said:
1 year ago
For km;
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
(2)
Sandeep said:
1 year ago
Agree, the answer is 150.
(6)
Kishan bhanja said:
1 year ago
Speed = 60 km/h = 60 * 5/18 = 50/3 m/s.
Time taken = 9 sec.
Length = speed * time = 50/3 * 9 =150 m.
Time taken = 9 sec.
Length = speed * time = 50/3 * 9 =150 m.
(5)
Anjali Singh said:
1 year ago
Should any one tell me how 5/18 came here?
(21)
James Gini said:
1 year ago
How we get 50, 3 and 18 in the solution?
(10)
Adeleye Jeremiah said:
1 year ago
Here it is asked for the length of the train and not the distance covered by the train. So anyone explain me this?
(4)
Vaishnavi said:
1 year ago
60 * 9 = 540,
540 * 5/18 = 150.
540 * 5/18 = 150.
(36)
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m/sec
Length of the train =