Aptitude - Problems on Trains - Discussion

Thanks for all your answers. It helps me a lot to understand.

How come 60*5/18 into 50/3? please explain.

@All.

We know that;
Velocity = Distance/Time.
so we can write,
Distance = Velocity*Time.
= (16.66)*(9) meters [=> 60km/hr convert into meters = 60*5/18. = 16.66 meter/sec.].
= 150 meters. [ANS].

Great, Thanks all for explaining the answer.

Super, thank you for your detailed explanation.

Thank you so much for all your explanation.

Thank you everyone for explaining the answer.

Thanks.

Thank you all for explaining very well.

According to antenna, which we design we say that frequency is between 1 to 5 Mhz or other think we can define values between 1 to 2 Mhz and can use them for infinite frequencies because if we consider frequency between 1 to 2 MHz then if we see then the output can be
1.1,1.111,1.115677,1.9876,1.11153565.....infinity now. Then why we are using this is because if you increase the value before a point it will have a large change as compared to adding values after the point.

And this is because even if there is a small change in frequency then both signals are uncorrelated to large extent.