Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 55 of 59.
Dharanish said:
6 years ago
Convert km to m - 60000.
Convert hr to sec - 3600.
60000/3600 = 16.666(speed)*9 (time) = 150.
Convert hr to sec - 3600.
60000/3600 = 16.666(speed)*9 (time) = 150.
Madhav Kulkarni said:
6 years ago
Train Speed is 60km/h ----- 60*(5/18)---------16.66 m/s.
time taken to cross the pole=9sec.
S=Distance(Length)/time.
s=16.66 time=9.
Distance(Length)=Speed*Time = 16.66*9 = 149.94 ===150.
So, Length = 150m.
time taken to cross the pole=9sec.
S=Distance(Length)/time.
s=16.66 time=9.
Distance(Length)=Speed*Time = 16.66*9 = 149.94 ===150.
So, Length = 150m.
Priya said:
6 years ago
@Koushik Reddy.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
Teju said:
5 years ago
Speed of train: 60km/hr,
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Tej said:
5 years ago
Very well explained. Thanks all.
Dharmaraj Gaikwad said:
5 years ago
Well explained, thanks.
Nayak said:
5 years ago
Well explained. Thanks all.
Monali said:
5 years ago
Very well explained, thanks all.
Harry said:
5 years ago
Very well explained, thanks all.
Shweta singh said:
5 years ago
Very well explained thank you guys.
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