Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
592 comments Page 55 of 60.
Bahauddin said:
6 years ago
Some thing is missing in the question and solution because if train crosses the pole means train will has to cross the extra length as much the length of train.
Savita said:
6 years ago
Nice explanation. Thanks all.
Koushik Reddy said:
6 years ago
Why we used 5|18 can you please explain it.
SRKS said:
6 years ago
If you will convert Speed of the train which is 60km/hr.
Then it will be ( 150/9)m/sec,
You get the answer directly which is 150m.
Then it will be ( 150/9)m/sec,
You get the answer directly which is 150m.
Sowndar said:
6 years ago
Can you explain the speed formula module?
Parem said:
6 years ago
Can you explain the speed formula module?
Dharanish said:
6 years ago
Convert km to m - 60000.
Convert hr to sec - 3600.
60000/3600 = 16.666(speed)*9 (time) = 150.
Convert hr to sec - 3600.
60000/3600 = 16.666(speed)*9 (time) = 150.
Madhav Kulkarni said:
6 years ago
Train Speed is 60km/h ----- 60*(5/18)---------16.66 m/s.
time taken to cross the pole=9sec.
S=Distance(Length)/time.
s=16.66 time=9.
Distance(Length)=Speed*Time = 16.66*9 = 149.94 ===150.
So, Length = 150m.
time taken to cross the pole=9sec.
S=Distance(Length)/time.
s=16.66 time=9.
Distance(Length)=Speed*Time = 16.66*9 = 149.94 ===150.
So, Length = 150m.
Priya said:
6 years ago
@Koushik Reddy.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
Teju said:
6 years ago
Speed of train: 60km/hr,
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
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