Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
613 comments Page 50 of 62.
Devkar Sunil said:
8 years ago
1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.
9sec=?.
Cross multipication =150m.
Sowmiya said:
8 years ago
Nice explanation, I understand your solution Thanks @Sundar.
Irine said:
8 years ago
I have one doubt.
Why don't you change 9sec into hours and then calculate distance?
Why don't you change 9sec into hours and then calculate distance?
Prasad said:
8 years ago
s=60*5/18,t=9;
s=d/t;
d=s*t=60*5/18*9=150;
s=d/t;
d=s*t=60*5/18*9=150;
Santhosh said:
8 years ago
Nice explanation. Thanks.
Dileepkumar said:
8 years ago
Nice explanation.
Shwetha said:
8 years ago
Very nice explanation. Thank you all.
Raja tiwari said:
8 years ago
60*5÷18*9=150.
Deepanshu Sharma said:
8 years ago
Am i the only one who sucks in logic?
Chithra said:
8 years ago
Thanks for all who have give explanation for this question, without your help I can't understand this problem.
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m/sec
Length of the train =