Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
120 metres
180 metres
324 metres
150 metres
Answer: Option
Explanation:

Speed = 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

Length of the train = 50 x 9 m = 150 m.
3

Discussion:
587 comments Page 43 of 59.

RISHI NIGAM said:   3 years ago
According to antenna, which we design we say that frequency is between 1 to 5 Mhz or other think we can define values between 1 to 2 Mhz and can use them for infinite frequencies because if we consider frequency between 1 to 2 MHz then if we see then the output can be
1.1,1.111,1.115677,1.9876,1.11153565.....infinity now. Then why we are using this is because if you increase the value before a point it will have a large change as compared to adding values after the point.

And this is because even if there is a small change in frequency then both signals are uncorrelated to large extent.

S. Gayathri said:   3 years ago
Speed = distance/time taken.
60 *1000 = length/ 9/3600.

1 hr = 3600 seconds.
9/3600*60*1000 = 150 m.

Adaeze Thompson said:   3 years ago
Thanks for the explanations.

Bharathi. D said:   3 years ago
Thanks all.

Bharathi. D said:   3 years ago
Thanks all for explaining the answer.

Brahma said:   3 years ago
Thank you everyone for explaining the answer.

Atungire Andrew said:   3 years ago
Thanks everyone for explaining.

Rahul said:   3 years ago
Thanks everyone for the answer.
(1)

Nithish.S said:   3 years ago
Convert km to m - 60000.
Convert hr to sec - 3600.

Sso, 60000/3600 = 16.666(speed) * 9 (time) = 150.
(22)

Santosh said:   3 years ago
Thanks all for explaining the answer.
(2)


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