Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 39 of 59.
Sada said:
9 years ago
@Muhammad.
This explanation is good and useful for beginners. Thankyou.
This explanation is good and useful for beginners. Thankyou.
Suresh said:
9 years ago
10/36 m/s
= 5/18 m/s.
Therefore 1 km/hr = 5/18 m/sec.
Similarly 60 km/hr = 60 x 5/18 m/sec.
I'm not understanding this section, please explain.
= 5/18 m/s.
Therefore 1 km/hr = 5/18 m/sec.
Similarly 60 km/hr = 60 x 5/18 m/sec.
I'm not understanding this section, please explain.
Makvana Disha said:
9 years ago
@Vishnu.
The value of N = 134.44.
The value of N = 134.44.
Shri said:
9 years ago
@Kalimuthu.
Short, simple and logically understandable answer .
Short, simple and logically understandable answer .
Afzal said:
9 years ago
Hello @Sundar,
I'm not understanding this 1 km/hr = 1000/3600 m/s.
But.
How come this?
= 10/36 m/s.
= 5/18 m/s.
Please explain.
I'm not understanding this 1 km/hr = 1000/3600 m/s.
But.
How come this?
= 10/36 m/s.
= 5/18 m/s.
Please explain.
Datta pawar said:
9 years ago
First convert value:
60km = 60000mtr.
1 hour = 3600sec.
Calculation.
60000/3600 = 16.666 mtr/sec (this value for only one meter).
So 9 * 16.666 = 150mtr.
60km = 60000mtr.
1 hour = 3600sec.
Calculation.
60000/3600 = 16.666 mtr/sec (this value for only one meter).
So 9 * 16.666 = 150mtr.
Gnanavel said:
9 years ago
If they asking to find the length of the pole, then how to solve it?
Vikas prasad said:
9 years ago
I can't solve the problem and also can't read it properly what can I do?
I.mahindra reddy said:
9 years ago
Nice and clear explanations. Thank you all.
Srinivasan said:
9 years ago
60000m = 6km.
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