Aptitude - Problems on Trains - Discussion

Nice explanation. Thanks.

1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.

Nice explanation, I understand your solution Thanks @Sundar.

When we say a train passes a pole in given time then basically we consider that pole as stationary point (having 0 speed) whose length is zero means actually train crosses its own length in given time frame. If we say a running train passes another train (stationery or running) then we have to consider the total length of two trains crossing each other also we have to consider the relative speed of the trains if both trains are running in same direction then relative speed is the difference of their speed and if both are running in opposite direction then their relative speed is sum of their speed.

1 km=3000m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.

Very useful explanation. Thanks.

Distance = Time *speed.
1km =1000Meteres,
1hr =3600 seconds,
Distance = 60*9/3600 =9/60 km,
Distane in Metres =(9/60)*1000 =150M.

Nice explanation. Thank you all.

Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres. How? explain me with simplification, please.

GIVEN:-
Speed of the train = 60 km/h.
Time = 9 sec.
Length of the train = ?

Formula : All lenth / time * 18/5 = speed.
Solution:-
All length/ time * 18/5 = 60,
?/9 * 18/5 =60,
? * 2/5 =60,
? * 1/5 = 30,
?*1 =30*5,
? = 150.
Answer :- 150 meter.