Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 30 of 59.
Subhasri said:
1 decade ago
Another easy method for solving it.
In 3600 sec the train go 60 km.
In 1 sec the train will go 1/60km.
Then in 9 sec it will go (1/60) *9 = .15km = 150 meter.
In 3600 sec the train go 60 km.
In 1 sec the train will go 1/60km.
Then in 9 sec it will go (1/60) *9 = .15km = 150 meter.
Anu said:
1 decade ago
Why is the length of train calculated with the formula speed*time?
Madhan said:
1 decade ago
They asked to find length of the train? but we gave an answer of distance traveled in 9sec, how these answers are same?
Vijay dabasiya said:
1 decade ago
Easy method.
1km=1000 m.
1 hr=3600 sec.
Formula length of = velocity*time.
= 60*1000/3600 *9.
= 150 m.
1km=1000 m.
1 hr=3600 sec.
Formula length of = velocity*time.
= 60*1000/3600 *9.
= 150 m.
Arunkumar said:
1 decade ago
It's simple but don't use our brain in finding the answer.
Santosh said:
1 decade ago
The problems and you people's explanation and coordination and sharing knowledge. I like these very much.
Najrul Shaikh said:
1 decade ago
Save = (1-0.55-0.15)x = 12,750.
Salary = x = 42,500.
Salary = x = 42,500.
NA shilpa said:
1 decade ago
Nice way of teaching maths who don't understand.
Sushmi said:
1 decade ago
Length of a train = (speed *time).
1 km - 1000 meter.
60 km - ?
60*1000 = 6000 meter = speed.
1 hr - 3600 seconds.
? - 9 second.
3600/9 = time.
So, LENGTH OF TRAIN = 6000*3600/9 = 150 METER.
THIS METHOD VERY EASY.
1 km - 1000 meter.
60 km - ?
60*1000 = 6000 meter = speed.
1 hr - 3600 seconds.
? - 9 second.
3600/9 = time.
So, LENGTH OF TRAIN = 6000*3600/9 = 150 METER.
THIS METHOD VERY EASY.
Sai Nath said:
1 decade ago
Length of the train = L.
L = Speed (s)*Time (T).
L = S*T.
L = 60*5/18*9.
L = 60*5/2.
L = 300/2=>L = 150 m.
L = Speed (s)*Time (T).
L = S*T.
L = 60*5/18*9.
L = 60*5/2.
L = 300/2=>L = 150 m.
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