Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 28 of 59.
Pradeep said:
1 decade ago
Distance = speed*time(50/2*9 = 150) m.
So, 150 m is distance traveled by the train, length of the train can be lower than distance. So can't say 150 m exact.
So, 150 m is distance traveled by the train, length of the train can be lower than distance. So can't say 150 m exact.
Kuldeep said:
1 decade ago
*Simple solution*
We know that,
1) 60km/1hr= 60000m/3600sec , (1hr=3600sec).
*Calulation = 60000/3600 = 16.66m/sec.
16.66x9 = 149.99 = 150m answer.
We know that,
1) 60km/1hr= 60000m/3600sec , (1hr=3600sec).
*Calulation = 60000/3600 = 16.66m/sec.
16.66x9 = 149.99 = 150m answer.
Raji said:
1 decade ago
I couldn't expect that for a single question which is having so many methods.
Abhi said:
1 decade ago
Can you explain this problem (sqrt(3N))^3/2 = 90?
Vijay katwal said:
1 decade ago
(60*1000*9)m/3600s = 150m.
Geetha(VG) said:
1 decade ago
Can you explain the encoding and decoding problems?
Siri said:
1 decade ago
I too want to know encoding and decoding?
Sanket said:
1 decade ago
Give me Different type of Examples on same logical base.
Sathya moorthy said:
1 decade ago
60 km/hr *speed= 60 x 5/18 m/sec.
Pinku said:
1 decade ago
Why in this question, you are saying to find out length of train it must be distance covered by the train?
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