Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
120 metres
180 metres
324 metres
150 metres
Answer: Option
Explanation:

Speed = 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

Length of the train = 50 x 9 m = 150 m.
3

Discussion:
587 comments Page 25 of 59.

Jagadeesh said:   1 decade ago
Here, give train travels at a speed of (60*5/18) m/s, that is for one second it travels a distance of 50/3 m/s. So the distance traveled for 9 seconds gives the actual length of train, that is 50/3*9=150m.

Kishan said:   1 decade ago
Similarly,

Speed = [60*5/18]m/sec=50/3 m/sec.

50/3*9 = 150mtrs.

Raj said:   1 decade ago
Speed = [60*5/18]m/sec=50/3 m/sec.

50/3*9 = 150mtrs.

Rasu said:   1 decade ago
Speed convert km/h to m/sec speed=[60*5/18]m/sec
speed=[50/3]m/sec.

Distance=[speed*time]
Length of the train=[50/3*9]
=150m.

SANTOSH, aps, goregaon said:   1 decade ago
Total exp= 15%+55%= 70%

Let salary rs.100

Save= 100-70= Rs.30%

Rs.30%= 12750.

100% = 12750/30x100=42500.

Udai said:   1 decade ago
How to convert m/sec in to km/hour?

Hari prasath said:   1 decade ago
How to convert feet into meter?

Ranjeet_Great said:   1 decade ago
@Udai.

Its very easy to convert m/sec in to km/hour,
Just multiply 18/5.

For example if we want to convert 5meter/sec in to km/sec then we will convert meter into km and sec in to hour.

That is 5meter=(5/1000)km and 1sec=(1/3600)hour.

So 5m/sec={(5/1000)/(1/3600)} km/hour.

or (5*3600)/(1*1000) km/hour

or (5*36)/(10) km /hour

or (5*18)/(5) km/hour

or 5 km/hour.

Anbu said:   1 decade ago
How to calculate percentage(%) in marketing?

Utpalkant said:   1 decade ago
To calculate% = (total obtain/total)*100.


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