Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 25 of 59.
Sagar said:
9 years ago
1 Hour = 60 Min.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
Swathi shetty p said:
9 years ago
Thanks to all.
Sathiyaraj said:
9 years ago
Cross 60000(60 km) meters in 3600 seconds(1 hour).
60,000 m => 3600 seconds,
100 m => 6 seconds,
Hence 3 sec => 50 m,
So, 100 + 50 mts = 150 m (6 + 3 = 9 seconds).
60,000 m => 3600 seconds,
100 m => 6 seconds,
Hence 3 sec => 50 m,
So, 100 + 50 mts = 150 m (6 + 3 = 9 seconds).
Akash said:
9 years ago
I agree with you @Satyapal.
Bhiva said:
9 years ago
Nice explanation @Parth.
Ranganath.S.J said:
9 years ago
Very nice explanation. Thank you to all.
Angelina said:
9 years ago
Easy to understand this method very nice explanation. Thank you to all.
Padma said:
9 years ago
I cannot understand this problem (6 * (5/18) * 9) = 150. Pease explains briefly.
Rupesh said:
9 years ago
Very good explanation @Sundar. Thank you.
Ravi said:
9 years ago
Awesome explanation @Sundar.
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