Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 23 of 59.
Datta pawar said:
9 years ago
First convert value:
60km = 60000mtr.
1 hour = 3600sec.
Calculation.
60000/3600 = 16.666 mtr/sec (this value for only one meter).
So 9 * 16.666 = 150mtr.
60km = 60000mtr.
1 hour = 3600sec.
Calculation.
60000/3600 = 16.666 mtr/sec (this value for only one meter).
So 9 * 16.666 = 150mtr.
DIVAKAR M S said:
9 years ago
Good explanation, I understood. Thank you all.
Srinivasan said:
9 years ago
60000m = 6km.
I.mahindra reddy said:
9 years ago
Nice and clear explanations. Thank you all.
Vikas prasad said:
9 years ago
I can't solve the problem and also can't read it properly what can I do?
Gnanavel said:
9 years ago
If they asking to find the length of the pole, then how to solve it?
Srinivas said:
9 years ago
Yeah@ obviously. Mr. Sundar your answer was right but I think your solution is complicated. I need as simple as possible. Will you provide?
Sonali said:
9 years ago
@Latha, Please explain the solution.
(sqrt(3N))^3/2 = 90.
N = 10.
(sqrt(3N))^3/2 = 90.
N = 10.
Ihhhh said:
9 years ago
I can't understand. Please help me.
Sonali said:
9 years ago
Hey, guise your answer is really good. But I have 1 prob how to convert km/hr 1000/3600. In that form 5/18.
But thanks to Arvind. I understand. How to convert. Really thanks again Arvind.
But thanks to Arvind. I understand. How to convert. Really thanks again Arvind.
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