Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
592 comments Page 17 of 60.
G david said:
7 months ago
Nice question. Thanks.
(3)
Gouthami said:
2 weeks ago
Good explanation. Thanks all.
(3)
Dhesappan said:
2 decades ago
Any one know the how many feet is one meter?
(2)
Sundar said:
2 decades ago
Feet to Meter conversion: 1 feet = 0.3048 meter
Meter to Feet conversion: 1 meter = 3.28083 feet
Meter to Feet conversion: 1 meter = 3.28083 feet
(2)
Rita said:
1 decade ago
Very well explained Sundar. Thanks a lot for helping us with your valuable explanation
(2)
Saranya said:
3 years ago
There for 9seconds convert into hours.
60km convert into meters.
9/3600 * 60000 = 150.
60km convert into meters.
9/3600 * 60000 = 150.
(2)
Santosh said:
3 years ago
Thanks all for explaining the answer.
(2)
Mohan said:
11 months ago
@All.
Here, Speed of the train = 60×(5/18) = 50/3.
Here, Speed of the train = 60×(5/18) = 50/3.
(2)
Gowrishankar said:
9 months ago
For km;
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
(2)
Pallavi Ananda Morbale said:
8 months ago
Very Good, Thanks everyone for explaining the answer.
(2)
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