Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
626 comments Page 17 of 63.
Kaustubh Kishor Salunkhe said:
1 year ago
@All Everyone,
For the people who asking how 5/18 came?
It is used to convert KMPH to MPS
Let me explain how and when to use it. The hint is in the Answers we can see 60 km/hr and answers in Meters.
If it's Vise Versa we will use 18/5 to get the answer in Kmph.
For the people who asking how 5/18 came?
It is used to convert KMPH to MPS
Let me explain how and when to use it. The hint is in the Answers we can see 60 km/hr and answers in Meters.
If it's Vise Versa we will use 18/5 to get the answer in Kmph.
(6)
Md shahid said:
1 year ago
The answer is 150m.
(6)
ABISHEK said:
1 year ago
150m is the correct answer.
(6)
Snehalatha said:
8 months ago
Good explanation, Thanks all.
(6)
Deep said:
7 months ago
Good question, Thanks all for explaining.
(6)
Mohammad jabir said:
6 months ago
Please explain this problem because I can't understand this.
(6)
Sana said:
4 months ago
Good explanation. Thanks all.
(6)
Poonam said:
3 months ago
It calculates as 600m->36 sec.
Then X->9sec.
By cross multiplication x =150m.
Then X->9sec.
By cross multiplication x =150m.
(6)
Rajakumara said:
3 years ago
It's a very good explanation to understand the equation. Thanks, everyone.
(5)
NARINDER KUMAR said:
3 years ago
9 = D*18/60 * 5 (USE S=D/T) AND (COVERT KM/HOUR IN TO M/SEC ) * 5/18.
So,
1 = D*2/300,
D = 300/2,
D = 150.
So,
1 = D*2/300,
D = 300/2,
D = 150.
(5)
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