Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
643 comments Page 15 of 65.
Raj said:
3 years ago
@All.
speed(60)*1000(KM convert to meters)/3600(Hoursconvrt to sec)
->60*1000/3600 = 60 * 5/18 = 50/3.
speed(60)*1000(KM convert to meters)/3600(Hoursconvrt to sec)
->60*1000/3600 = 60 * 5/18 = 50/3.
(9)
Anil Magar said:
3 years ago
@Anuradha.
= 50/3*9.
= 16.6666667*9,
= 150M answer.
= 50/3*9.
= 16.6666667*9,
= 150M answer.
(9)
Saumya tripathi said:
2 years ago
Yes, the answer should be 150.
(9)
Revanth said:
2 years ago
How 5%18 came? could anyone please explain?
(9)
Suraj balaji kshirsagar said:
2 years ago
150 is the correct answer.
(9)
Akhil Joseph K J said:
2 years ago
Calculation: 60× (5 / 18)
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
(9)
Kamalesh Kamalesh said:
1 year ago
Agree, 150 is the correct answer.
(9)
Gayathri avula said:
4 months ago
Very useful. Thanks all for explaining.
(9)
Karthick said:
2 decades ago
Nice explanation for beginners.
(8)
Kalimuthu said:
2 decades ago
1000m=1km so 60000m goes in 1hour.
1 hour=3600 sec so 60000/3600 =16.666 so train cross in 1 second is 16.666m...so 9 seconds 16.6666*9=150meter .
1 hour=3600 sec so 60000/3600 =16.666 so train cross in 1 second is 16.666m...so 9 seconds 16.6666*9=150meter .
(8)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers

m/sec
Length of the train =