Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
598 comments Page 12 of 60.
Sariga Ashokkumar said:
3 months ago
A km/hr = [a×5÷18]m/s.
60 = [9×5÷18].
5÷2×60 = 150 meter.
60 = [9×5÷18].
5÷2×60 = 150 meter.
(13)
Shyam Prasanth said:
3 years ago
= 60×5/18.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
(12)
MANDARA GADADE KN said:
3 weeks ago
How we can take 5/18? Please explain.
(12)
Kurnool ranjith said:
2 years ago
How 5 came?
(11)
Yash said:
8 months ago
150 is the correct answer.
(11)
Rohit Chouhan said:
7 months ago
First we converted into m/s to speed.
So length = speed *time.
So, length =50 * 3 = 150.
So length = speed *time.
So, length =50 * 3 = 150.
(11)
Christo said:
3 years ago
The length of the train can be anything! why are we taking distance from the initial point to the pole?
Please explain.
Please explain.
(10)
Nkem victory said:
2 years ago
How did you get 18 and 50? Please explain.
(10)
BIENVENU GBETI said:
2 years ago
How the term 60 come? Please explain me.
(10)
Adesh Katiya said:
2 years ago
s = 60km/hr
Time to cross pole = 9sec.
l = ?.
Time(train of length l) (pass a pole) = time(to cover l meters).
So,
9s = dist(l)/60km/hr
9s = dist(l)/1/6ms
9s = 6*dist
3/2 = dist
1.5 = dist
Hence option (d).
Time to cross pole = 9sec.
l = ?.
Time(train of length l) (pass a pole) = time(to cover l meters).
So,
9s = dist(l)/60km/hr
9s = dist(l)/1/6ms
9s = 6*dist
3/2 = dist
1.5 = dist
Hence option (d).
(10)
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