Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 12 of 59.
Geetha(VG) said:
1 decade ago
Can you explain the encoding and decoding problems?
Siri said:
1 decade ago
I too want to know encoding and decoding?
Sanket said:
1 decade ago
Give me Different type of Examples on same logical base.
Sathya moorthy said:
1 decade ago
60 km/hr *speed= 60 x 5/18 m/sec.
Pinku said:
1 decade ago
Why in this question, you are saying to find out length of train it must be distance covered by the train?
Muni said:
1 decade ago
60 km/hr *speed = 60 x 5/18 m/sec.
Giri said:
1 decade ago
1 km = 1000 meters.
1 hr = 3600 seconds.
1 km/hr = 1000/3600 m/s.
1 hr = 3600 seconds.
1 km/hr = 1000/3600 m/s.
Qaazi said:
1 decade ago
Where has the 50/3 come from? please explain.
Moupiya said:
1 decade ago
Train Cross Stationary object without length.
t = Lt/St.
Lt = length of train.
St = speed of train.
Can I follow this formula for this question as I follow made easy book and for this type of question this formula is used but I'm not getting the answer thru this formula.
Can any 1 help.
Thankyou.
t = Lt/St.
Lt = length of train.
St = speed of train.
Can I follow this formula for this question as I follow made easy book and for this type of question this formula is used but I'm not getting the answer thru this formula.
Can any 1 help.
Thankyou.
Prashanth said:
1 decade ago
Speed = (60*(5/18)) divide 60&18 by 6, then,
Speed = (10*(5/3)) multiply 10 & 5,
Speed = (50/3).
That's all @Qaazi.
Speed = (10*(5/3)) multiply 10 & 5,
Speed = (50/3).
That's all @Qaazi.
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