Aptitude - Problems on Trains - Discussion

Given, that.

Speed=60 km/hr.
Time=9 sec.
Time is given in sec so we convert the given speed km/hr into sec.

So, 60*5/18 m/sec=50/3 m/sec.
Therefore, the length of the train is =>speed * time.
50/3*9= 150 m/s.

60 km/hr = 60 * 1000m/60 * 60 = 50/3m/s.

#speed = distance/time,
1km = 1000m,
1hr = 60m&
1min = 60s.

Then Length(l) = speed * time
l = 50/3 * 9 = 1350/9.
l = 150m.

@Anuradha.
= 50/3*9.
= 16.6666667*9,
= 150M answer.

Given that:

Speed of the Train : 60 km/h.
Crosses pole in Seconds : 9 s.

1 km = 1000 meters.
1 km/h = 60 x 1000 meters.

(i.e,) Distance = 60,000 meters.

1 hour = 60 minutes and 1 min = 60 seconds.
1 hour = 60 x 60,
(i.e,) Time = 3600 s,

Speed of the train = Distance/Time.
= 60000 m/3600 s.
= 600 m/36 s.
= 100 m/6 s.
= 50/3 meters per sec.

Length of train = Speed x Time.
= 50/3 x 9,
= 450/9.
= 150 m.

Therefore, the answer is option(D)

How we get 50/3? Please explain.

How did 5/18 came here? please explain.

60 * 60 = 3600,
1000/3600 = 5/18,
60Km/hr.
1km = 1000m,
1hr = 60min.
1sec = 60sec.

Speed = 60 KM/H.
D = ?
T = 9 S.
[Km/h - M/s = 5/18] [M/s - Km/h = 18/5].
Speed is in km/h and time is in seconds.
Convert the speed from km/h to M/s.
So,
Speed = 60 * 5/18 = 50/3 (Fraction).
D = 50/3 * 9 =450/3 = 150 M.

60 Km/hr.
1 km = 1000 m
1 hr = 60 min.
1 min = 60 sec.

Converting km/hr into m/sec.
1000m / 3600sec = 5/18,
So, we got this 5/18, Got it.

Now, Just multiply this by the actual value,
(Distance = Speed × Time),
that is; 60 * 5/18 = 50/3 m/sec and this distance is for one sec.

For 9 sec,
multiply 50/3 by 9.
50/3 * 9 = 150m.

How we can get 5/18 meters per second?