Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 8)
8.
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: Option
Explanation:
| Formula for converting from km/hr to m/s: X km/hr = |  |
X x | 5 |  |
m/s. |
| 18 |
| Therefore, Speed = | |
45 x | 5 | m/sec |
= | 25 | m/sec. |
| 18 | 2 |
Total distance to be covered = (360 + 140) m = 500 m.
| Formula for finding Time = | |
Distance | |
| Speed |
 Required time = |
|
500 x 2 | sec |
= 40 sec. |
| 25 |
Discussion:
78 comments Page 8 of 8.
Ankit Shukla said:
1 decade ago
I think total distance is 360+140+360 = 860 m.
Because the length is started from the starting point to end point of the train.
Because the length is started from the starting point to end point of the train.
Vishal said:
1 decade ago
Not train is add own length + Pass platform length.
E.g: Train length 345.
Platform 456.
Train length + Platform length.
345+456 = 801.
Now you got it.
E.g: Train length 345.
Platform 456.
Train length + Platform length.
345+456 = 801.
Now you got it.
Joydeep mukherjee said:
1 decade ago
There are no starting and end point mentioned in the question.
Whenever, you get this type of question, just.
Total length = 360+140 m = 500 m.
Whenever, you get this type of question, just.
Total length = 360+140 m = 500 m.
Saiteja said:
1 decade ago
Train speed = 45 km/hr.
= 45*(5/18) = 12.5 m/sec.
140 m long bridge cross in = 140/12.5 = 11.2 sec.
Including train length crossing time i.e. 360/12.5 = 28.8 sec.
Total = 11.2+28.8 = 40 sec.
= 45*(5/18) = 12.5 m/sec.
140 m long bridge cross in = 140/12.5 = 11.2 sec.
Including train length crossing time i.e. 360/12.5 = 28.8 sec.
Total = 11.2+28.8 = 40 sec.
Aditya said:
1 decade ago
From where did 45*(5/18) came please explain?
Prasun jana said:
1 decade ago
Speed = 45*(5/18) = 12.5.
= (360+140)/12.5 = 40.
= (360+140)/12.5 = 40.
Chetan said:
1 decade ago
Discussion was very nice it's very clear to all.
Syed khamar said:
1 decade ago
S = 45*5/18 => 25/2.
Now train passes platform = 360+140/25/2.
= 500*2/25.
= 40 sec.
Now train passes platform = 360+140/25/2.
= 500*2/25.
= 40 sec.
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