Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 8)
8.
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: Option
Explanation:
Formula for converting from km/hr to m/s: X km/hr = | ![]() |
X x | 5 | ![]() |
m/s. |
18 |
Therefore, Speed = | ![]() |
45 x | 5 | ![]() |
= | 25 | m/sec. |
18 | 2 |
Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = | ![]() |
Distance | ![]() |
Speed |
![]() |
![]() |
500 x 2 | ![]() |
= 40 sec. |
25 |
Discussion:
78 comments Page 2 of 8.
Shubham Jain said:
6 years ago
How come 25/2?
(1)
Nibha said:
6 years ago
Why 140m is added?
(1)
Rohan said:
6 years ago
Why we have to add the length of the train?
Sai said:
6 years ago
450mts ----> 36sec.
500mts ---> 40sec.
500mts ---> 40sec.
(1)
Anush said:
6 years ago
Why we are adding the train length with bridge length?
(1)
Prasad kapal said:
7 years ago
But we added 500 with 140.
Gurwinder singh said:
7 years ago
Why (x*5/18) mps?
ANIL said:
7 years ago
Given,
length of the train =360m,
speed of train =45km/h,
length of the bridge =140m,
time =T.
Now convert 45km/h=45*5/18=225/18m/s.
Total length=360m+140m=500m.
We know speed =distance/time.
=> 225/18=500/T.
=> T=500*18/225.
=> T=40s.
length of the train =360m,
speed of train =45km/h,
length of the bridge =140m,
time =T.
Now convert 45km/h=45*5/18=225/18m/s.
Total length=360m+140m=500m.
We know speed =distance/time.
=> 225/18=500/T.
=> T=500*18/225.
=> T=40s.
Lavi chaudhary said:
7 years ago
@All.
First of all, 360*5/18=1800/18=100 and finally 140-100=40 ans.
First of all, 360*5/18=1800/18=100 and finally 140-100=40 ans.
Sarang said:
7 years ago
Distance = speed *time.
360+140=45*5/18*time,
500=5*5*/2*time,
500=25/2*time,
500=12.5*time,
500/12.5=time,
Time = 40 second.
360+140=45*5/18*time,
500=5*5*/2*time,
500=25/2*time,
500=12.5*time,
500/12.5=time,
Time = 40 second.
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