Aptitude - Problems on Numbers - Discussion

I didn't get it.

Can anyone explain ?

Please.

10 to 99.
10, 11, 12, 13, 14, 15, 16, 17.......
10+01=11; 12+21=33; 13+31=44; 14+41=55.
Eg: 28+82=110;

Any two numbers from 10 to 99 gets interchange of 10 unit position to one unit position and one unit position to 10 unit position and do sum of the numbers that particular number will be definitely divisible 11.

Very easy yar.

Take 10,11,......99 any number.
Just interchange position then add it,
Say 23+32 = 55.
24+42 = 66.
10+01 =11.
45+54 = 99.

It is very easy,

Check with answer, in answer two-digit number is 11.

Then interchange it will '11'.

Then add old and new is = 11+11 = 22.

Sum:22, check with choice 22 is divisible by 11.

Take any two numbers. For ex take 63+36=99. So 99 is divisible by 11. If we take any two numbers all that numbers are only divisible by 11 only. So answer is 11.

Like santosh it is really simple just start by taking
12....21.,
at first attempt option 5 and 9 cancelled out
at second attempt 13....31 we get ans is 11.

It's very simple..
for example take a two digit number : i.e 45
the reverse of the number is 54

So 45+54= 99(which is a divisible of 11)

Wow karishma yaar you are so talented sahi samzaya answer.

Now I got it.

Two digits No. means any of the number from 10 to 99.
let us take 98 as a 2 digit number. In this number 9 tens and one 8 is there. 9 tens means 9x10. that is 90 and one 8 is being added. So that we can get 98.
That is why they have mentioned as ten's digit.

for your understanding we will take a 98743265.

In this number 5 is in the place of one, 6 is 10th, 2 is 100th, 3 is 1000th, 4 is 10,000th,7 is 1,00,000th 8 is 10,00,000th and 9 is 1,00,00,000th.

Why did they take ten digits number in the solution of question because in question they have mentioned 2 digits no ?