Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 6)
6.
The sum of the digits of a two-digit number is 15 and the difference between the digits is 3. What is the two-digit number?
Answer: Option
Explanation:
Let the ten's digit be x and unit's digit be y.
Then, x + y = 15 and x - y = 3 or y - x = 3.
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.
So, the number is either 96 or 69.
Hence, the number cannot be determined.
Discussion:
41 comments Page 1 of 5.
Jambay said:
5 years ago
The answer will be 96 only as question specify that x-y as 3 not -3.
So the answer is 96 only.
So the answer is 96 only.
(17)
Amit said:
10 months ago
It should be 96 as 9 + 6 = 15 and 9 - 6 = 3. It satisfies the given condition.
Correct me, if I am wrong.
Correct me, if I am wrong.
(11)
Sakshi said:
1 year ago
Let the two-digit number be( 10x + y ), where ( x ) is the tens digit and ( y) is the unit digit.
We are given two conditions:
1. The sum of the digits is 15: [ x + y = 15 ]
2. The difference between the digits is 3: [ x - y = 3]
Now, we can solve these two equations simultaneously:
From the second equation,
x = y + 3
Substitute this value of ( x ) into the first equation:
(y + 3) + y = 15.
2y + 3 = 15.
2y = 12.
Then, y = 6.
Now substitute y = 6 into ( x = y + 3 ):
x = 6 + 3 = 9
Thus, the two-digit number is ( 10x + y = 10(9) + 6 = 96).
The two-digit number is 96.
We are given two conditions:
1. The sum of the digits is 15: [ x + y = 15 ]
2. The difference between the digits is 3: [ x - y = 3]
Now, we can solve these two equations simultaneously:
From the second equation,
x = y + 3
Substitute this value of ( x ) into the first equation:
(y + 3) + y = 15.
2y + 3 = 15.
2y = 12.
Then, y = 6.
Now substitute y = 6 into ( x = y + 3 ):
x = 6 + 3 = 9
Thus, the two-digit number is ( 10x + y = 10(9) + 6 = 96).
The two-digit number is 96.
(6)
Mrinu said:
5 years ago
Two digit no are 10x+y.
Let assume x > y.
x + y = 15.
x - y = 3,
x = 9 & y=6.
Number- 10*x+y= 10*9+6 = 96.
if y>x.
10*6 + 9 = 69 .
So, the answer cannot be determined.
Let assume x > y.
x + y = 15.
x - y = 3,
x = 9 & y=6.
Number- 10*x+y= 10*9+6 = 96.
if y>x.
10*6 + 9 = 69 .
So, the answer cannot be determined.
(3)
Dominic said:
1 decade ago
If we take 69 as answer.
Sum becomes:6+9=15.
But difference become: 6-9=-3.
But from the question, the sum should be 15 and the difference 3, not -3. On this note, I strongly believe that, the correct answer is 96, because.
Sum: 9+6=15,
And difference: 9-6=3.
Sum becomes:6+9=15.
But difference become: 6-9=-3.
But from the question, the sum should be 15 and the difference 3, not -3. On this note, I strongly believe that, the correct answer is 96, because.
Sum: 9+6=15,
And difference: 9-6=3.
(1)
Visalini said:
3 years ago
x+y=15,
x-y=3.
Adding both the equation.so,
2x = 18,
x = 9.
Put x=9 in any equation,
9-y=3,
-y=-5,
Y=5.
The answer is;
X = 9.
Y = 5.
x-y=3.
Adding both the equation.so,
2x = 18,
x = 9.
Put x=9 in any equation,
9-y=3,
-y=-5,
Y=5.
The answer is;
X = 9.
Y = 5.
(1)
Marvellous David said:
5 years ago
I don't understand where they got that x=6 and y=9. Please anyone explain me.
(1)
Aayush... said:
5 years ago
Good morning friends.
Let the numbers X and Y
(1).X+Y = 15.
(2).X-Y = 3.
From equation (1)
X+Y = 15
Y = 15 -X .
Adding equation (1)and (2)
We get --- X - ( 15 - x) = 3.
When we solve this we get X = 9 and Y = 6.
BUT
When we solve another method.
Let the numbers X and Y.
(1).X+Y = 15.
(2).X-Y = 3.
From equation (1).
X + Y = 15.
X = 15 - Y.
Adding equation (1)and (2).
We get --- (15 - Y) - Y = 3.
When we solve this we get X = 6 and Y = 9.
So, the answer is either 96 or 69.
So, here the answer is cannot be determined.
Thanks.
Let the numbers X and Y
(1).X+Y = 15.
(2).X-Y = 3.
From equation (1)
X+Y = 15
Y = 15 -X .
Adding equation (1)and (2)
We get --- X - ( 15 - x) = 3.
When we solve this we get X = 9 and Y = 6.
BUT
When we solve another method.
Let the numbers X and Y.
(1).X+Y = 15.
(2).X-Y = 3.
From equation (1).
X + Y = 15.
X = 15 - Y.
Adding equation (1)and (2).
We get --- (15 - Y) - Y = 3.
When we solve this we get X = 6 and Y = 9.
So, the answer is either 96 or 69.
So, here the answer is cannot be determined.
Thanks.
(1)
Muhammadkhan said:
7 years ago
Let tens digit is = x.
And unit digit is = y.
Here x+y=15 ------> 1
x-y = 3 ------> 2
From two:
x=3+y put it in 1 we will get y = 6.
Now put y in equation 1 we get x = 9.
As x is ten digit and y is unit so, 10 * x +y = 10 * 9 + 6 = 96.
So 96 is the correct answer.
And unit digit is = y.
Here x+y=15 ------> 1
x-y = 3 ------> 2
From two:
x=3+y put it in 1 we will get y = 6.
Now put y in equation 1 we get x = 9.
As x is ten digit and y is unit so, 10 * x +y = 10 * 9 + 6 = 96.
So 96 is the correct answer.
(1)
Snehal said:
6 years ago
What is correct answer?
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