Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Discussion:
86 comments Page 5 of 9.
SHANKAR said:
6 years ago
Simply we can solve this by;
1+6+8+3=18
1+6+7+7=21
Same as other;
18 is divided by 9 and then B is correct.
1+6+8+3=18
1+6+7+7=21
Same as other;
18 is divided by 9 and then B is correct.
Shubham shah said:
8 years ago
Answer is just simple divide all option values by 9 which is exactly divisible is your answer. Just simple.
Shruti said:
8 years ago
@Suchita.
You are truly right this really works!
Must say this is the best Sol for this question. Thanks.
You are truly right this really works!
Must say this is the best Sol for this question. Thanks.
Bodla aravind said:
6 years ago
Let (840k + 3) = 1683 [ 1683 taken from Option B].
Therefore, k = (1683-3)/840.
k = 1680/840,
k= 2.
Therefore, k = (1683-3)/840.
k = 1680/840,
k= 2.
Mehar said:
1 decade ago
multiply all the values ==> 5*6*7*8=1680.
these are leaving 3 as a reminder so,1680+3=1683.
these are leaving 3 as a reminder so,1680+3=1683.
Swati padewal said:
5 years ago
Simply we can solve this by,
5*6*7*8 = 1680.
And then after 1680+3 = 1683
The answer is 1683.
5*6*7*8 = 1680.
And then after 1680+3 = 1683
The answer is 1683.
(12)
Sunita said:
9 years ago
If there is no option is given, and the question is asking sum of that no what will we do?
Bujji said:
1 decade ago
Simply divide the options with 9 and which option whose remainder is 0 it is the answer.
Rupesh said:
2 decades ago
All thing I understand but how this value of k is taken 2 can som one explain me.
Ritvik said:
10 years ago
Best possible way to add the digits in the option and check divisibility with 9.
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