Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
88 comments Page 8 of 9.
Aqsa said:
1 decade ago
@ Krishan Rajwar u made me laugh.u r good.
Adi said:
7 years ago
How 90k+4 ?
Please explain this step.
Please explain this step.
Choudhary said:
6 years ago
What if the value of k has very large?
(1)
Neetu said:
1 decade ago
90k+4/7=4
How is please explain it.
How is please explain it.
Priya said:
9 years ago
How Lcm of 90 come? Please explain.
Sherin lazar said:
4 months ago
Thank you all for explaining answer.
Dashi said:
7 years ago
Thanks for the answer @Jignesh.
Codi said:
3 years ago
Thanks for explaining @Rahul.
(2)
SATYA said:
9 years ago
How find the value of k==4?
Jyoti said:
1 decade ago
How the value k=4 comes?
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