Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
88 comments Page 8 of 9.
V!cky said:
10 years ago
Divide all given answer by 7 when remainder remains 0 i.e correct answer or assume k.
Take LCM i.e 90 K+4.
Take LCM i.e 90 K+4.
Sravanthi said:
1 decade ago
It is given in the question that it should be least multiple of 7 which leaves remainder 4. So why don't it be 94. Please clarify.
Sundar said:
1 decade ago
Four different numbers are given. So take k=4 that's all.
Manisha said:
1 decade ago
Please, tell the how you calculate the value of k=4?
Ram said:
1 decade ago
k=4 because we need least value of k which is divided 7.
So in equation 90k+4. If k=4 then answer is 364 which is divisible by 7.
So in equation 90k+4. If k=4 then answer is 364 which is divisible by 7.
Ananth said:
1 decade ago
Shortest Way => Only one option divisible by 7 is "364".
SRI said:
1 decade ago
You will have 90k+4.
Now we know 90/7 gives - 12.85 so, we can write 90 as 84k+6k.
So 90k+4 can be written as (84k)+6k+4. The first part 84k is divisible by 7. So no need to check. The second part i.e. 6k+4 has to be divisible by 7.
K = 1, 6(1)+4 = 10 X.
K = 2, 6(2)+4 = 16 X.
K = 3, 6(3)+4 = 22 X.
K = 4, 6(4)+4 = 28.
So this is divisible by 7 hence your answer is 84(4)+6(4)+4.
Hope this clarifies.
Now we know 90/7 gives - 12.85 so, we can write 90 as 84k+6k.
So 90k+4 can be written as (84k)+6k+4. The first part 84k is divisible by 7. So no need to check. The second part i.e. 6k+4 has to be divisible by 7.
K = 1, 6(1)+4 = 10 X.
K = 2, 6(2)+4 = 16 X.
K = 3, 6(3)+4 = 22 X.
K = 4, 6(4)+4 = 28.
So this is divisible by 7 hence your answer is 84(4)+6(4)+4.
Hope this clarifies.
Sonu said:
2 decades ago
How can you find the value of k=4 i.e.
How we can divide (90k + 4)by 7.
How we can divide (90k + 4)by 7.
Srishti said:
1 decade ago
Here is a simple logic.
First find the LCM of the no.s which comes 90.
Now find the no. among the options greater than 90 and divisible by 7.
First find the LCM of the no.s which comes 90.
Now find the no. among the options greater than 90 and divisible by 7.
Amita said:
1 decade ago
First read the q. when we divide the all options with 6 then we get the reminder 4 in three option's 1st is 94 and 2nd 184 and 3rd is 364. when we divide the 94 and 184 with 7 we will get it is not divisible by 7, but when we divide the 364 with 7 then we get this is divisible by 7 so it will be answer.
After this only 364 is divisible by 7
7)364(52
-35
------
014
- 14
-------
00
-------
Another way is,
Divide all 4 option with 7. you will easily get which no. is divisible by 7.
And you will get only 364 is divisible by 7 so answer is 364.
6)74(12 6)94(15 6)364(6 6)184(3
-6 -6 -36 -18
----- ----- ------ ------
14 34 004 004
-12 -30
----- -----
02 04
After this only 364 is divisible by 7
7)364(52
-35
------
014
- 14
-------
00
-------
Another way is,
Divide all 4 option with 7. you will easily get which no. is divisible by 7.
And you will get only 364 is divisible by 7 so answer is 364.
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