Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
89 comments Page 8 of 9.
Sachin said:
1 decade ago
Given here the answer should be multiple of 7, so simply divide all options by 7.
Then we only got the answer 364.
Then we only got the answer 364.
Anurag nist said:
1 decade ago
No need to find ok...
Just substitute k=1,k=2,k=3,....so on.
The question asks for least number....
The moment you get that the num is divisible by 7. stop there....
I hope u got it.
Just substitute k=1,k=2,k=3,....so on.
The question asks for least number....
The moment you get that the num is divisible by 7. stop there....
I hope u got it.
Sakthivel C.M said:
1 decade ago
How did you find K ?
Aqsa said:
2 decades ago
@ Krishan Rajwar u made me laugh.u r good.
Manasa said:
2 decades ago
Thank you sundar.
Sundar said:
2 decades ago
Short cut method: [ Eliminating the options method ]
From this "The least multiple of 7" - we can tell the the result should be divisible by 7.
From the given 4 options, 364 is the only number divisible by 7.
Therefore, 364 is the correct answer.
From this "The least multiple of 7" - we can tell the the result should be divisible by 7.
From the given 4 options, 364 is the only number divisible by 7.
Therefore, 364 is the correct answer.
Jignesh rajput said:
2 decades ago
Here, (90k+4) put each of value starting from 1,2,3,.... than after divisible by 7.when in the case of put 4th value we have not get the any remainder of (90k+4)divisible by 7..dats y take k=4.
i.e (90(1)+4)/7= remainder 3
(90(2)+4)/7= remainder 3
(90(3)+4)/7= remainder 2
(90(4)+4)/7= remainder 0
thats y take k=4.
thanks u
i.e (90(1)+4)/7= remainder 3
(90(2)+4)/7= remainder 3
(90(3)+4)/7= remainder 2
(90(4)+4)/7= remainder 0
thats y take k=4.
thanks u
Neetu said:
2 decades ago
90k+4/7=4
How is please explain it.
How is please explain it.
Neetu said:
2 decades ago
How k's value is 4 9k+4/7= k=4.
Please clear it.
Please clear it.
Habibali@mail.com said:
2 decades ago
Thankx Rahul...
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