Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
88 comments Page 5 of 9.
Jaisri said:
6 years ago
6, 9, 15, 18 LCM is 90.
Least number from this is 6. So 90+6= 96 when 96÷7 is 73 then remainder is 4.
Least number from this is 6. So 90+6= 96 when 96÷7 is 73 then remainder is 4.
Shalini said:
6 years ago
LCM of 6, 9, 15, 18 is 90.
Such that there is one formula these type of questions ie "LCM*k+remainder "should be divisible by a multiple.
So we want to do "trail and error" method by giving value from the options to the 'k' so that the number is divisible, so we substitute k=4.
Such that there is one formula these type of questions ie "LCM*k+remainder "should be divisible by a multiple.
So we want to do "trail and error" method by giving value from the options to the 'k' so that the number is divisible, so we substitute k=4.
Sherin lazar said:
4 months ago
Thank you all for explaining answer.
Sherin lazar said:
4 months ago
Thank you everyone for explaining the session clearly.
Neetu said:
1 decade ago
How k's value is 4 9k+4/7= k=4.
Please clear it.
Please clear it.
Meenakshi said:
1 decade ago
@bhavi,
The trick which was said by krishna was very simple and even though you ask for a short trick ?
The trick which was said by krishna was very simple and even though you ask for a short trick ?
Sowmya said:
1 decade ago
94 is divisible by 7 and it leaves a reminder of 4 when divided with all other given numbers so y not 94?
Koti reddy said:
1 decade ago
How to come k=4 ?
Sachin said:
1 decade ago
Given here the answer should be multiple of 7, so simply divide all options by 7.
Then we only got the answer 364.
Then we only got the answer 364.
Anurag nist said:
1 decade ago
No need to find ok...
Just substitute k=1,k=2,k=3,....so on.
The question asks for least number....
The moment you get that the num is divisible by 7. stop there....
I hope u got it.
Just substitute k=1,k=2,k=3,....so on.
The question asks for least number....
The moment you get that the num is divisible by 7. stop there....
I hope u got it.
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