Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
88 comments Page 2 of 9.
O jung beom said:
9 years ago
No need to be messed up. Here we are given a clue (multiple of 7) it means the no is to be divided by 7. We got only 364 divisible with 7.
Now just make a test by dividing 364 by 6. As it leaves a remainder of 4 so 364 is the correct answer.
Now just make a test by dividing 364 by 6. As it leaves a remainder of 4 so 364 is the correct answer.
SUBHANKAR DAS said:
4 years ago
L.C.M. of 6, 9, 15, and 18 is 90.
Let the required number be 90k + 4, which is a multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4,as it is not divisible if k=1,2,3
So, the Required number = (90 x 4) + 4 = 364.
Let the required number be 90k + 4, which is a multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4,as it is not divisible if k=1,2,3
So, the Required number = (90 x 4) + 4 = 364.
(2)
Bhavesh said:
4 years ago
90K+4 is the required number.
If K=1,
90*1+4=94 , it is not multiple of 7.
90*2+4=184,it is not multiple of 7,
90*3+4=274,it is not multiple of 7,
90*4+4=364,it is multiple of 7,
So, the least value will be 364.
If K=1,
90*1+4=94 , it is not multiple of 7.
90*2+4=184,it is not multiple of 7,
90*3+4=274,it is not multiple of 7,
90*4+4=364,it is multiple of 7,
So, the least value will be 364.
(58)
Aditya Kulkarni said:
6 years ago
@All.
Here, We have been asked for a least multiple of 7, therefore one of the numbers given in option must be divided by 7.
74, 94 and 184 are not divisible by 7, but 364 is. So, 364 is the answer.
Here, We have been asked for a least multiple of 7, therefore one of the numbers given in option must be divided by 7.
74, 94 and 184 are not divisible by 7, but 364 is. So, 364 is the answer.
(1)
Navnath said:
4 years ago
As sample as that.
If the number is multiple of 7 then Obviously it should divide by 7.
Then check all the options by dividing 7.
Look only one option that is 364 is completely divided by 7.
If the number is multiple of 7 then Obviously it should divide by 7.
Then check all the options by dividing 7.
Look only one option that is 364 is completely divided by 7.
(20)
Anurag nist said:
1 decade ago
No need to find ok...
Just substitute k=1,k=2,k=3,....so on.
The question asks for least number....
The moment you get that the num is divisible by 7. stop there....
I hope u got it.
Just substitute k=1,k=2,k=3,....so on.
The question asks for least number....
The moment you get that the num is divisible by 7. stop there....
I hope u got it.
Shakir said:
7 years ago
Here you can check from option also which is divisible of 7 like;
74 is not completely divided by 7.
Same as 94 and 184 also, But 364 is completely divisible by 7, So 364 is the answer.
74 is not completely divided by 7.
Same as 94 and 184 also, But 364 is completely divisible by 7, So 364 is the answer.
(1)
Anonymous said:
1 decade ago
But in this question, the least number is 4. However, what if the number is too large. Will we have to try with every number in place of k and keep checking if it is divisible on not?
Chanchal said:
8 years ago
90k + 4/7 find k.
90k/7 + 4/7.
We have to distribute 90 k as multiple of 7 and divisible by 7.
12 * 7k + 6k + 4/7.
12 * 7k/7 + 6k + 4/7.
Now we can put the value of k in 6k+4/7.
90k/7 + 4/7.
We have to distribute 90 k as multiple of 7 and divisible by 7.
12 * 7k + 6k + 4/7.
12 * 7k/7 + 6k + 4/7.
Now we can put the value of k in 6k+4/7.
Bappi sah said:
8 years ago
By formula;.
Given reminder is 4, and divisor is 6, 9, 15, 18 and lcm of 6, 9, 15, 18 is 90. To find dividend we have to multiply 90 with remainder 4 and then add remainder ie 4.
Given reminder is 4, and divisor is 6, 9, 15, 18 and lcm of 6, 9, 15, 18 is 90. To find dividend we have to multiply 90 with remainder 4 and then add remainder ie 4.
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