Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 12)
12.
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 4 and 3 = 60.
On dividing 2497 by 60, the remainder is 37.
Number to be added = (60 - 37) = 23.
Discussion:
40 comments Page 2 of 4.
Karthick said:
10 years ago
Nos is 2497 opt 3, 13, 23, 33 which divide 3, 4, 5, 6.
Add each one:
2497+3 = 2500.
2497+13 = 2510.
2497+23 = 2520.
2497+33 = 2530.
3 divides only when addition of those no is divisible by 3.
So 2500 = 7 not divide.
2510 = 8
2520 = 9 divide.
Add each one:
2497+3 = 2500.
2497+13 = 2510.
2497+23 = 2520.
2497+33 = 2530.
3 divides only when addition of those no is divisible by 3.
So 2500 = 7 not divide.
2510 = 8
2520 = 9 divide.
Manjeet Sidhu said:
9 years ago
After LCM is 60.
Now we want to know which number is added to make divided 2497 with 60.
2497/60 = 41 but there is remeder is 37 and we want to fully divided so add 23 from the option.
Best of luck.
Now we want to know which number is added to make divided 2497 with 60.
2497/60 = 41 but there is remeder is 37 and we want to fully divided so add 23 from the option.
Best of luck.
Gannu said:
1 decade ago
@Prashanthy K.
Like 2497/60 does give 37 as remainder so that doesn't mean that it contains 37 60's because 37x60 \= 2497.
It is remainder, not quotient.
Can anyone explain why 60-37.
Like 2497/60 does give 37 as remainder so that doesn't mean that it contains 37 60's because 37x60 \= 2497.
It is remainder, not quotient.
Can anyone explain why 60-37.
Veeresh said:
9 years ago
Add 3,13,23,33 to 2497 separately.
2494 + 3 = 2500 likewise then these factors 5, 6, 4, 3 divided to the result it must be 0 i.e. 2497 + 23 = 2520 it is divided by 5, 6, 4, 3.
2494 + 3 = 2500 likewise then these factors 5, 6, 4, 3 divided to the result it must be 0 i.e. 2497 + 23 = 2520 it is divided by 5, 6, 4, 3.
Saumya singh said:
7 years ago
On dividing 2497 by 60 so the remainder will not become 37. The right remainder will become 41.61.
So why it is 37 here, could you please explain?
So why it is 37 here, could you please explain?
(4)
Poonam said:
1 decade ago
What would have been the case if we are asked to find the highest no. Which should be added to 2497?
Then are we supposed to add 37 to 2497 ?
Then are we supposed to add 37 to 2497 ?
Vijay said:
1 decade ago
Guys please see option and each option on number and using divisibility rule. Check if it is perfectly divisible or not.
ZIA said:
1 decade ago
Sol: LCM of 5,6,4,3 is 60.
On dividing 2497 by 60 we get 37 as remainder.
Therefore number to added is 60 - 37 =23.
On dividing 2497 by 60 we get 37 as remainder.
Therefore number to added is 60 - 37 =23.
Madhu said:
1 decade ago
Can anyone explain how the sum is exactly divisible by 5, 6, 4 and 3?
Sum of 23 is divisible only by 5 right?
Sum of 23 is divisible only by 5 right?
ANITA said:
10 years ago
5*1 = 5.
2*3 = 6.
2*2 = 4.
3*1 = 3.
5*1*2*3*2*2*3*1.
5*2*3*2 = 60.
2497/60 = Remainder 37.
60-37 = 23.
2*3 = 6.
2*2 = 4.
3*1 = 3.
5*1*2*3*2*2*3*1.
5*2*3*2 = 60.
2497/60 = Remainder 37.
60-37 = 23.
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