Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 24)
24.
Which of the following fraction is the largest ?
7
8
13
16
31
40
63
80
Answer: Option
Explanation:

L.C.M. of 8, 16, 40 and 80 = 80.

7 = 70 ;   13 = 65 ;   31 = 62
8 80 16 80 40 80

Since, 70 > 65 > 63 > 62 , so 7 > 13 > 63 > 31
80 80 80 80 8 16 80 40

So, 7 is the largest.
8

Discussion:
49 comments Page 3 of 5.

Rakesh said:   1 decade ago
7/8=70/80, 13/16=65/80, 31/40=62/80 this answer how to come?

Md. Khurshid said:   1 decade ago
I think @Hanumanth is right, because it is easiest way to check the correct answer that which fraction is larger or smaller.

Deepti said:   1 decade ago
The answer given by @Hanumanth is not applicable to all kinds of questions with same nature. I have tried. Its wrong.

Amita said:   1 decade ago
(a) 7/8 (b) 13/16 (c) 31/40 (d) 63/80.

First of all I compare b/t a and b with cross multiplication.

7/8, 13/16.

7*16 13*8.

112 >104.

So 7/8>13/16.

Again compare b/t 7/8 and 31/40.

7*40 31*8.

280 > 248, so 7/8>31/40.

Again compare b/t 7/8 and 63/80.

7*80 8*63.

560 > 504, so 7/8>63/80.

So 7/8 is largest.

Glory said:   1 decade ago
Hi guys,

Which one is correct in simple way am confused with your solutions, I need to understand how to use L.C.M in solving that question?

Manju said:   1 decade ago
Hai guys!

The following fractions are 7/8, 13/16, 31/40, 63/80.

If we take 7/8. First we have to sub these (8-7 =1 ) and divide numerator with 1 (7/1 = 7) same process.

13/16, 16-13 = 3 13/3 = 4.3.

31/40, 40-31 = 9 31/9 = 3.4.

63/80, 80-63 = 17 60/17 = 3.94.

By this we can easily say that 7, 4.3, 3.94, 3.4.

(this process we can applicable for descending and ascending order).

Dhanya said:   1 decade ago
LCMof 8, 16, 40, 80 is 80 only. It is correct.

Sowmya said:   1 decade ago
I think answer given by @Hanumanth is right and easy. But is it applicable to all problems ?

Viswa said:   1 decade ago
Its wrong lcm of 8,16,40,80 = 160 not 80.
(1)

Shyam said:   1 decade ago
Dear @Naveenkk can you please explain with details as @Hanumanth.

And is this method applicable to all this type of problems. Like those don't have common divisor.


Post your comments here:

Your comments will be displayed after verification.