Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 26)
26.
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
Answer: Option
Explanation:
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
= H.C.F. of 1651 and 2032 = 127.
Discussion:
38 comments Page 2 of 4.
Janaiah said:
8 years ago
Thanks @Krishna.
Nidhi said:
8 years ago
Please explain the solution of this question.
Jenifer said:
8 years ago
Why should we find HCF? Why not LCM?
Sayeeda said:
8 years ago
Thank you @Deepak.
K sreenivasulu said:
9 years ago
Thank you @M. V. Krishna.
Rajan gupta said:
9 years ago
Please explain the method to calculate the HCF with an example.
Albert said:
9 years ago
Please explain the calculation of H.C.F in detail.
Shivam said:
9 years ago
If we divide 7 by 2 it gives a remainder of 1.
Either we add or subtract the remainder 1 from 7 the numbers obtained 8 and 6 which is divisible by 2.
How the answer come in this problem, that we have to add or subtract?
Either we add or subtract the remainder 1 from 7 the numbers obtained 8 and 6 which is divisible by 2.
How the answer come in this problem, that we have to add or subtract?
Prabhakaran said:
1 decade ago
@Thayagarajan. How we know 127 is the correct answer?, that's we need tell clearly.
Thyagarajan said:
1 decade ago
Answer:
13*127 = 1651+6 = 1657.
16*127 = 2032+5 = 2037.
13*127 = 1651+6 = 1657.
16*127 = 2032+5 = 2037.
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