Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)
4.
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Answer: Option
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Discussion:
158 comments Page 9 of 16.
Helena said:
1 decade ago
The clue is in the question. A digit by definition is any number between 0 & 9.
N = 1120.
The digits of 1120 are the digits, 1, 1, 2, 0.
There are four of them.
Hope that helps.
N = 1120.
The digits of 1120 are the digits, 1, 1, 2, 0.
There are four of them.
Hope that helps.
Sahid said:
1 decade ago
8 will divide each number and leave reminder 1, and 8 is greatest among all of the option.
Manish said:
1 decade ago
People try dividing each number by 8 and you will get the same remainder.
Adarsha Gowda Mandya said:
1 decade ago
Hello @Sarswathi, why are you taking 10 to multiply number after the subtraction. Could you please tell me?
Gopalakrishnan said:
1 decade ago
@All.
Is very simple to find the answer!
In question clearly given N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. So we dividing the each number by giving option as 4 5 6 8 and we get same remainder as option A) 4.
Is very simple to find the answer!
In question clearly given N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. So we dividing the each number by giving option as 4 5 6 8 and we get same remainder as option A) 4.
Suleman said:
1 decade ago
People try dividing each number by 8 and you will get the same remainder.
RAVI JAIN said:
1 decade ago
EASY ONE NO. ARE 6905, 4665, 1305
SO [(6905-1305)-(4665-1305)] / 2 = [2240] / 2 = 1120.
NOW 1+1+2+0 = 4.
SO [(6905-1305)-(4665-1305)] / 2 = [2240] / 2 = 1120.
NOW 1+1+2+0 = 4.
Chandra said:
1 decade ago
[(6905-1305)-(4665-1305)] / 2 = [2240] / 2 = 1120.
@Ravi can you explain how you did this step?
@Ravi can you explain how you did this step?
Sujit said:
1 decade ago
Why to take the difference between no.s? I don't get it.
Mehak said:
1 decade ago
Why we have to add 1+1+2+0? I'm not getting it. Please someone explain it.
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