Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)
4.
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Answer: Option
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Discussion:
158 comments Page 4 of 16.
Dev said:
5 years ago
The HCF of any numbers would necessarily have to be a factor of the difference between any pair of numbers.
Here it is asked that find the number which when divides 4665, 6905 and 1305 give the same remainder.
So, to find this, we can find the HCF of the difference between these three numbers.
This number will be the greatest number which when divides 4665, 6905 and 305 gives the same remainder.
Here it is asked that find the number which when divides 4665, 6905 and 1305 give the same remainder.
So, to find this, we can find the HCF of the difference between these three numbers.
This number will be the greatest number which when divides 4665, 6905 and 305 gives the same remainder.
(1)
Anita Chettri said:
5 years ago
N = HCF of (4665-1305),(6905-4665) and (6905-1305).
= HCF of 3360,2240 and 5600.
= 2*2*2*2*2*5*7
= 1120.
Sum of digits in N = (1+1+2+0) = 4.
= HCF of 3360,2240 and 5600.
= 2*2*2*2*2*5*7
= 1120.
Sum of digits in N = (1+1+2+0) = 4.
(4)
Anita Chettri said:
5 years ago
N = HCF of (4665-1305),(6905-4665)and (6905-1305).
= HCF of 3360,2240 and 5600,
= 2 * 2 * 2 * 2 * 2 * 5 * 7.
= 1120
Sum of digits in N = (1+1+2+0) = 4.
= HCF of 3360,2240 and 5600,
= 2 * 2 * 2 * 2 * 2 * 5 * 7.
= 1120
Sum of digits in N = (1+1+2+0) = 4.
(1)
Haq ahmed said:
5 years ago
How we get the 1120 HCF of those number, can someone explain? please.
Vihaan said:
5 years ago
I can't understand why are we taking the numbers (4665 - 1305), (6905 - 4665) and (6905 - 1305)?
Can anyone please explain to me this in brief?
Can anyone please explain to me this in brief?
(1)
Jack said:
5 years ago
I can't understand why we are taking H.C.F. Of (4665 - 1305), (6905 - 4665) and (6905 - 1305).
Anyone please explain in detail.
Anyone please explain in detail.
(1)
Prince Khan said:
5 years ago
Thanks for the answer @Saraswati.
Jaya said:
5 years ago
Thanks @Saraswati.
Anom said:
6 years ago
Great explanation, Thanks @M. Harish.
Vishnu Sai said:
6 years ago
I have a question.
Can anyone please explain why they are taking the HCF of (4665-1305), (6905-4665) and (6905-1305) i.e. the HCF of 3360, 2240 and 5600.
Also in the question it states the remainder should be same, it does not state the remainder should only be zero.
So I wish some of the other clarifies my doubts.
Can anyone please explain why they are taking the HCF of (4665-1305), (6905-4665) and (6905-1305) i.e. the HCF of 3360, 2240 and 5600.
Also in the question it states the remainder should be same, it does not state the remainder should only be zero.
So I wish some of the other clarifies my doubts.
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