Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)
4.
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Answer: Option
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Discussion:
157 comments Page 2 of 16.
Zara said:
1 decade ago
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4, how does it come and What N indicates?
Shanmugar said:
1 decade ago
Let they find the hcf of 3 numbers is that. 1350, 4665, 6905.
Why are they finding the hcf of 3360, 2240, 5600. And one more thing in the question they have that N divides this numbers with same reminder they didn't mention that "N exactly divides" or reminder is zero.
Why are they finding the hcf of 3360, 2240, 5600. And one more thing in the question they have that N divides this numbers with same reminder they didn't mention that "N exactly divides" or reminder is zero.
Yogesh said:
1 decade ago
HCF of 2240(smallest); 3360(middle); 5600(largest no)
Hence hcf ===1120
2240* ) 3360 ( 1
2240
------
1120** )2240* ( 2
2240
-------
0000
-------
1120**)5600 ( 5
5600
------
0000
------
Hence hcf ===1120
Savitha said:
1 decade ago
Good explanation yogesh:).
Ramya said:
1 decade ago
Thankx priya.
Chirag said:
1 decade ago
Saraswati your explanation is superb.
Ashwin said:
1 decade ago
Why are they finding H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) ?
Please explain.
Please explain.
Kumar said:
1 decade ago
Thanks yogesh.
Souravikiran said:
1 decade ago
Hi yogeash can you explain me the basic logic of hcf and lcm. How did we take numbers after factorising and what about co prime and the logic of selecting common factors. Please.
Shakti said:
1 decade ago
Thanks! saraswati.
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