# Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)

4.

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Answer: Option

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Discussion:

152 comments Page 15 of 16.
Shanmugar said:
1 decade ago

Let they find the hcf of 3 numbers is that. 1350, 4665, 6905.

Why are they finding the hcf of 3360, 2240, 5600. And one more thing in the question they have that N divides this numbers with same reminder they didn't mention that "N exactly divides" or reminder is zero.

Why are they finding the hcf of 3360, 2240, 5600. And one more thing in the question they have that N divides this numbers with same reminder they didn't mention that "N exactly divides" or reminder is zero.

Zara said:
1 decade ago

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4, how does it come and What N indicates?

Swati said:
1 decade ago

Why we are taking the HCF of (4665 - 1305) , (6905 - 4665) and (6905 - 1305).

Plzzz explain.

Plzzz explain.

Vishal said:
1 decade ago

Thanks saraswati.

Jinx said:
1 decade ago

Thanks sarsu.

Neha said:
1 decade ago

Thanx priya.

Saraswati said:
1 decade ago

First do this(4665 - 1305) , (6905 - 4665) and (6905 - 1305). we ll get 3360,2240,5600. then divide by 10.. now

336=2*2*2*2*3*7*10

224=2*2*2*2*2*7*10

560=2*2*2*2*5*7*10

So take the common multiples.. now we got 2*2*2*2*7*10=1120( this 1120 is "N")

So, question asked here is sum of digits "N"??

"N" is 1120; sum of digits "N" is 1+1+2+0=4.

Tats it!;)

336=2*2*2*2*3*7*10

224=2*2*2*2*2*7*10

560=2*2*2*2*5*7*10

So take the common multiples.. now we got 2*2*2*2*7*10=1120( this 1120 is "N")

So, question asked here is sum of digits "N"??

"N" is 1120; sum of digits "N" is 1+1+2+0=4.

Tats it!;)

(2)

SWARNA said:
1 decade ago

How we know by seeing the numbers the H.C.F ?

Prashanthi said:
1 decade ago

1120*3=3360

1120*2=2240

1120*5=5600

the highest common factorial num is:1120 for all 3 numbers

so that here 1+1+2+0=4 we got.....

1120*2=2240

1120*5=5600

the highest common factorial num is:1120 for all 3 numbers

so that here 1+1+2+0=4 we got.....

Priya said:
1 decade ago

Upto my understanding

(4665 - 1305)=3360, (6905 - 4665)=2240 and (6905 - 1305)=5600

3360:2240:5600

1120:1120:1120

So, Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Hope so,if am wrong means correct me

(4665 - 1305)=3360, (6905 - 4665)=2240 and (6905 - 1305)=5600

3360:2240:5600

1120:1120:1120

So, Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Hope so,if am wrong means correct me

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