Aptitude - Problems on H.C.F and L.C.M - Discussion

Is this the common HCF problem if so when I try to solve it using Euclid's method I got the answer '1'.

Am I right?

Is there anyone who will clearly explain why one has to take the difference of those numbers?

I mean what is the key note in the question seeing which I will solve the problem in this way?

Please explain someone.

43/4 the remainder is 3. 91/4 the remainder is 3. 183/4 the remainder is 3. So, finally we get the answer 4.

I'm confused by this one, Please explain with division method.

I don't understand I'm only eleven, please someone help me to get this.

Hi @Ajeeth, very simple for the H.C.F.

For the numbers, you have given (455, 522 & 533).

H.C.F=1, Because the factor of these numbers are 455 = 1 x 5 x 7 x 13,
522 = 1 x 2 x 261 &
533 = 1 x 533.

So except 1, no digit is common in each number. Hence the common digit 1 is the H.C.F of above numbers.
This is the common rule of finding H.C.F. That those digit/digits which will be common in all the numbers.

Eg. You have to find the H.C.F. of 24, 60 & 81. Now factors of each number will be 24 = 2 x 2 x 2 x 3, 60 = 2 x 2 x 3 x 5, & 81 = 3 x 3 x 3 x 3.

Here only the digit '3' is common in all, hence 3 will be H.C.F of these numbers. Also note that if more than 1 digit is common in all the numbers then multiplication of those digits will be the H.C.F (suppose 2 & 5 both are common in all the numbers then the multiplication of both the digit will be 10) hence 10 will be the H.C.F of those numbers.

Thanks.

How to take HCF I don't know how to take HCF please anybody explains me. How to find the HCF for any unknowns for ex: 533, 522, 455 for this number?

Everything is fine, but I am getting doubt with HCF. In three numbers common we get 2. If we divided 2 * 2 * 2 get 8. Why are you telling 4?

What are the numbers to find the difference?

All this explanation are not clear to me. Please explain it in a simple way.