Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
216 comments Page 22 of 22.
Arya said:
2 decades ago
If three nos as in this case is 43, 91 and 183 are given then to find HCF the shortest solution is take the diff:
1) 91 - 43 = 48 (4*3*7)
2) 183 - 91 = 92 (4*23)
3) 183 - 43 = 140 (4*7*5)
Thus the HCF is 4.
1) 91 - 43 = 48 (4*3*7)
2) 183 - 91 = 92 (4*23)
3) 183 - 43 = 140 (4*7*5)
Thus the HCF is 4.
Anirudh rai said:
2 decades ago
Is this the only way to this type of problem?
If yes then would you please explain it.
If yes then would you please explain it.
Raj said:
2 decades ago
Why do we do the difference of number to each other?
(1)
Sourabh Das said:
2 decades ago
I also want an explanation about the logic of the solution.
Anu said:
2 decades ago
Explain the logic of this solution.
Nagu said:
2 decades ago
Why they took difference between those nos.
Please explain me.
Please explain me.
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