Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 5 of 21.
Mahima Chaurasia said:
7 years ago
In the question it is asked the remainder should be same so, Answer is option A ie 4.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
Shanmukh Adari said:
7 years ago
Your explanation is fantastic, Thank you so much @Prashant.
Sixface said:
7 years ago
It's very simple guys =>
43/4=3,
92/4=3,
183/4=3.
The remainder is 3 for all divide so 4 is the correct answer.
43/4=3,
92/4=3,
183/4=3.
The remainder is 3 for all divide so 4 is the correct answer.
Chary said:
7 years ago
Thanks for giving nice explanation @Prasanth.
Ahmad Zaidi said:
7 years ago
@Samir.
First find the LCM of 60, 80, 90, which is 720. Then divide it by 99999 which is highest 5 digit number, and less the reminder which is 639 and answer is 99360. Which is equally divisible by 60, 80, 90. Thanks.
First find the LCM of 60, 80, 90, which is 720. Then divide it by 99999 which is highest 5 digit number, and less the reminder which is 639 and answer is 99360. Which is equally divisible by 60, 80, 90. Thanks.
G vinay said:
7 years ago
How? Please explain the answer.
Ankush said:
7 years ago
@Mrunmay.
Solution they take difference because to make remainder zero. And than that divisor will divine these number Completely.
Solution they take difference because to make remainder zero. And than that divisor will divine these number Completely.
Jyothi said:
8 years ago
Not getting it, can anyone please explain it?
Mrunmay said:
8 years ago
Why numbers are being subtracted? I still have a doubt. Please explain me.
Mahima said:
8 years ago
Nice explanation @Parthiban. Thanks.
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