Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

214 comments Page 3 of 22.

Ayesha said: 4 years ago

I am not understanding this. Please explain in detail.

(17)

Ram rao said: 4 years ago

Thanks everyone for explaining the answer.

(3)

Narendra Singh said: 4 years ago

Thanks everyone for explaianing.

(4)

Anomie said: 5 years ago

P is called the divisor & not dividend.

(Divisor x quotient) + remainder= dividend.

(1)

Ishaq said: 5 years ago

Thanks everyone for explaining.

Darshil said: 5 years ago

Why they subtracted? Explain, please.

Aravind B said: 5 years ago

Thanks all for giving the clear explanation.

Sakthi said: 5 years ago

Why they took difference here? Anyone explain about it.

Nic said: 5 years ago

Same remainder means? Please anyone explain for me.

Tejveer said: 5 years ago

@Karthik V.

Great explanation, Thanks for solving this.

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