Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 20 of 21.
Habib said:
1 decade ago
The difference is taken to analyze the pattern. Amongst the numbers !
Ie each difference tells us that these numbers are multiples of 4 and have the same remainder because all numbers can be divided by 4.
Hence you get 4.
Ie each difference tells us that these numbers are multiples of 4 and have the same remainder because all numbers can be divided by 4.
Hence you get 4.
Komal said:
1 decade ago
The difference is used to get the common factors between two nos. it will eliminate the uncommon factors.
And at-last we have only to pick up the highest common factor...
you can try with an example for 30 and 10.
factors of (30) = 5,2,3
factors of (10) = 5,2
factors of (30-10) = 5,2
And at-last we have only to pick up the highest common factor...
you can try with an example for 30 and 10.
factors of (30) = 5,2,3
factors of (10) = 5,2
factors of (30-10) = 5,2
Sweety said:
1 decade ago
I don't understand why we need to find the difference. Please explain the logic behind it.
Titus said:
1 decade ago
That is true. Understanding is more important.
Durga said:
1 decade ago
Getting answer is not important but knowing how to approach that answer is important. Thanks for Prashant.
Pankaj maharaj said:
1 decade ago
Yesss! you sud simply divide and find the ans in quicker way.
Navneet said:
1 decade ago
Divide each with each option.
Hind said:
1 decade ago
I go with same method as shweta and dhanasekar has said in the forum.
Nam said:
1 decade ago
Acc to the formulae H.C.F. of [(H.C.F. of any two) and (the third number)] gives the H.C.F. of three given number.
So as per the first formulae the hcf of 183 & 43 is comming 10
n the third no. is 91 so how will 4 be the ans
So as per the first formulae the hcf of 183 & 43 is comming 10
n the third no. is 91 so how will 4 be the ans
Dhanasekar said:
1 decade ago
Simply try divide to divide each by the options, by this which is exactly divided then that is the answer.
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