Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
4
7
9
13
Answer: Option
Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

     = H.C.F. of 48, 92 and 140 = 4.

Discussion:
216 comments Page 14 of 22.

Prem said:   1 decade ago
I am unable to understand this problem. Can anyone explain all steps involved?

Kumari said:   1 decade ago
Dear friends, Why they took difference between them and is any other easy as well as short method ? please communicate this answer as soon as possible. Thanking you.

Sarath said:   1 decade ago
I think the smarter way will be to divide the numbers with options and check. But your speed has to be so high.

Tahir said:   1 decade ago
Just simple according to the question there is no compilation is 43/4 the reminder is 3 then 91/4 the remainder is 3 and now 183/4 the reminder is once again three. F look at question the reminder is same ie 3.

Rajvir singh said:   1 decade ago
Why do need to take difference three times? (91-43), (183-91) was enough. and then take h.c.f. of 48 and 92 please someone give another example why do we need to do (183-43)?

Mani pandian said:   1 decade ago
Here are the list of prime factors of 24 and 36:

24 = 2 x 2 x 2 x 3.
36 = 2 x 2 x 3 x 3.

If we write down the numbers that are the same in both lists, they will give us the highest common factor of 24 and 36:

HCF of 24 and 36 is 2 x 2 x 3 = 12.

This is the meaning of H.C.F.

Afsa said:   1 decade ago
Some one help! What is the logic behind H. C. F?

Sharmi said:   1 decade ago
Why you have to divide all the number with 4. What is the reason, please explain?

Jaggu said:   1 decade ago
43%4 = 3.

91%4 = 3.

183%4 = 3.

That's why answer is 4.

Niveditaa singh said:   1 decade ago
Is this only method to solve this?

If it can be solve by another way then please explain.


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