Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 18)
18.
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:
Answer: Option
Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
Discussion:
36 comments Page 2 of 4.
Reuben said:
1 decade ago
hcf of any two numbers is a factor of those two numbers .. means example if u take hcf of 12 and 18 .. its 6 .. it means 6 is a factor of 12 and 18. 6*2=12 6*3=18
now if i say there are two numbers in ratio 2:3 whose hcf is 6 how will u write the two numbers ??
solve my question and u will understand it
ans: hcf*2 is one number hcf*3 is the other
now if i say there are two numbers in ratio 2:3 whose hcf is 6 how will u write the two numbers ??
solve my question and u will understand it
ans: hcf*2 is one number hcf*3 is the other
(1)
Rahul said:
7 years ago
3x ,4x be the two numbers and the given Question HCF is given so take HCF of (3, 4) = 1x.
So x = 4.
3*4=12,
4*4=16,
LCM = 48.
So x = 4.
3*4=12,
4*4=16,
LCM = 48.
JC N said:
10 years ago
Since the ratio is given and the HCF as well, we now know that there will not be any other factor other than the ratio * HCF for both the numbers. Because if there are any more factors then the HCF will increase by that number. So the two numbers have to be 3*HCF and 4*HCF.
Eg: Suppose we say that HCF is not the only other factor than the number could be 3*HCF*x and 4*HCF*Y, now for the ratio to be 3:4, x = why. But x=why then we have another common factor for the two numbers and the HCF would then be HCF*x which is not true as per the given question. Thus, there should be no other common factor. Thus, we can say whenever the ratio and HCF are given the numbers are always ratio * HCF.
Eg: Suppose we say that HCF is not the only other factor than the number could be 3*HCF*x and 4*HCF*Y, now for the ratio to be 3:4, x = why. But x=why then we have another common factor for the two numbers and the HCF would then be HCF*x which is not true as per the given question. Thus, there should be no other common factor. Thus, we can say whenever the ratio and HCF are given the numbers are always ratio * HCF.
Rupesh said:
8 years ago
Hcf = product/lcm.
= 3*4+4*4/4.
= 48.
= 3*4+4*4/4.
= 48.
Kushal said:
9 years ago
Here given two ratios are 3:4 and given HCF is 4 so that's the highest common factor so one can think that could be multiple of 3:4.
So just multiplied with 3*4 and 4*4 so two numbers we get are 12 and 16 take out LCM by 12->2*2*3 and of 16->2*2*2*2-> 2*2*3*2*2->48.
So just multiplied with 3*4 and 4*4 so two numbers we get are 12 and 16 take out LCM by 12->2*2*3 and of 16->2*2*2*2-> 2*2*3*2*2->48.
Pranathi said:
9 years ago
4 * lcm=3x * 4x.
4 * lcm=3 * 4 * 4 * 4,
Lcm = 12 * 16 ÷ 4.
= 48 -> Is this correct?
4 * lcm=3 * 4 * 4 * 4,
Lcm = 12 * 16 ÷ 4.
= 48 -> Is this correct?
Onkar Rana said:
9 years ago
Why they put x = 4? Explain me.
Dipali Patkar said:
9 years ago
@Ashif.
18 * 16 = 288.
18 * 16 = 288.
ASHIF said:
10 years ago
The product of HCF 18 and LCM 16 is?
Can anyone help to get the answer?
Can anyone help to get the answer?
Pritam said:
1 decade ago
Initially let the two numbers be 3x and 4x and there given h.c.f is 4.
So that means 3*x and 4*x are the product of a number and a variable which is = to the product of h.c.f and l.c.m as we know.now h.c.f given here is 4.
So put 4 instead of x and get the numbers i.e 12 and 16.
Find the l.c.m of these two numbers i.e 48.
So that means 3*x and 4*x are the product of a number and a variable which is = to the product of h.c.f and l.c.m as we know.now h.c.f given here is 4.
So put 4 instead of x and get the numbers i.e 12 and 16.
Find the l.c.m of these two numbers i.e 48.
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